我以前在这里看到过类似的问题,但他们似乎都在谈论只获得最小值或最大值。我需要同时获得两者,最好是通过一个查询。我无法理解这在 MySQL 中是如何工作的逻辑。
示例数据
+--------+--------+---------+---------+----------+
|temp_min|temp_max|pressure |condition|dt_txt |
+--------+--------+---------+---------+----------+
|9.27 |9.27 |1021.98 |Rain |2018-05-15|
|8.77 |8.77 |1021.22 |Rain |2018-05-15|
|9.99 |9.99 |1021.31 |Clear |2018-05-15|
|13.86 |13.86 |1021.41 |Clouds |2018-05-15|
|12.39 |12.39 |1019.71 |Rain |2018-05-14|
|13.42 |13.42 |1020.24 |Rain |2018-05-14|
|14.14 |14.14 |1020.41 |Rain |2018-05-14|
|9.01 |9.01 |1018.12 |Rain |2018-05-14|
|13.94 |13.94 |1020.73 |Rain |2018-05-14|
|5.64 |5.64 |1018.42 |Clouds |2018-05-14|
|10.65 |10.65 |1021.8 |Clouds |2018-05-14|
|8.69 |8.69 |1018.91 |Clouds |2018-05-14|
|... |... |... |... |... |
+--------+--------+---------+---------+----------+
逻辑和常识会决定这样的事情:
SELECT
MIN(`temp_min`) AS `temp_min`,
MAX(`temp_max`) AS `temp_max`,
`dt_txt`,
DAYNAME(`dt_txt`) AS `dayname`,
`pressure`,
`condition`,
`dt_txt`
FROM
infoboard.forecasts
WHERE `dt_txt` >= CURDATE()
GROUP BY `dt_txt`
ORDER BY `dt_txt` ASC;
结果是:
+--------+--------+---------+---------+----------+--------+
|temp_min|temp_max|pressure |condition|dt_txt | |
+--------+--------+---------+---------+----------+--------+
|10.65 |9.01 |1018.12 |Rain |2018-05-14|Monday |
|13.86 |9.99 |1021.98 |Rain |2018-05-15|Tuesday |
+--------+--------+---------+---------+----------+--------+
For 2018-05-14min 应该是8.69,max 应该是14.14
For 2018-05-15min 应该是8.77,max 应该是13.42
如何从 temp_* 列中获取真正的最小值和最大值以及驱动正确查询的逻辑是什么?