1

我有一个如下的xml。

<list>
    <map>
    <map name="CLAIM_TICKET_1">
    <val name="CLAIM_TICKET_Groups">Kalyan</val>
    <val name="Testing">Ram</val>
    </map>
    <map name="CLAIM_TICKET_2">
    <val name="CLAIM_TICKET_Groups">Raju</val>
    <val name="Testing">Varma</val>
    </map>
    </list>

我试图使用消化器将其检索为 Map 对象。

我想要输出为:

作为 Map 对象的列表。

{CLAIM_TICKET_1={CLAIM_TICKET_Groups=Kalyan,Testing=Ram},
CLAIM_TICKET_2={CLAIM_TICKET_Groups=Raju,Testing=Varma}}

我的代码显示错误:

字符串 Xpath = "地图/地图";

digester.addObjectCreate(Xpath, HashMap.class);
    digester.addCallMethod(Xpath , "put", 2);
    digester.addCallParam(Xpath, 0, "name");        

    digester.addObjectCreate(Xpath, HashMap.class);
    digester.addCallMethod(Xpath+"/val" , "put", 2);
    digester.addCallParam(Xpath+"/val", 0, "name");        
    digester.addCallParam(Xpath+"/val", 1);

    digester.addSetNext(Xpath+"/val", "put"); 
4

1 回答 1

0
    String Xpath = "map/map";
//For every occurence of list/map add map object to list object
    digester.addObjectCreate("list/map", ArrayList.class);

    digester.addObjectCreate(Xpath, HashMap.class);
    digester.addCallMethod(Xpath+"/val" , "put", 2);
    digester.addCallParam(Xpath+"/val", 0, "name");        
    digester.addCallParam(Xpath+"/val", 1);

digester.addSetNext("list/map", "add"); 


It works fine.
于 2011-03-07T08:54:58.167 回答