8

我正在使用错误边界组件来捕获反应错误,它工作正常。

我的问题是,在生产应用程序中,日志记录有点用处,因为组件堆栈看起来像这样:

\n    in t\n    in t\n   in t\n    in t\n    in t\n    in div\n    in t\n    in u\n    in n\n    in t\n    in t

在开发环境中,组件堆栈更有用:

in ErrorPage (created by Route)\n    in Route (at Routes.js:60)\n    in Switch (at Routes.js:46)\n    in Router (created by BrowserRouter)\n    in BrowserRouter (at Routes.js:45)\n    in div (at Routes.js:43)\n    in ThemeProvider (at theme.js:1262)\n    in Theme (at Routes.js:42)\n    in Provider (at Routes.js:41)\n    in ErrorBoundary (at Routes.js:40)\n    in Routes (at index.js:12)

消息也是如此。在生产中我们得到:

t.value (http://localhost:3333/static/js/main.5a3e606e.js:1:680858

在开发中:

Uncaught TypeError: Person is not a constructor
at ErrorPage._this.click2 (ErrorPage.js:12)

有没有办法让反应错误映射到源代码并使日志记录在生产中实际可用?

更新:我正在使用一个名为http://js.jsnlog.com/的库来处理日志并实际捕获所有内容(甚至是事件处理程序)。这就是边界组件看起来像https://pastebin.com/aBFtD7DB的样子。问题不是捕捉错误,而是在生产中它们是无用的。

4

2 回答 2

6

我使用库https://www.stacktracejs.com/找到了解决方案。

StackTrace.report() 方法将获取地图并为您提供所需的未缩小信息!

所以现在我的 React 边界看起来像这样。我仍然使用 window.onerror 来确保我抓住了一切。

首先,确保将stacktrace-gps和添加stacktrace-js到您的 package.json

import React, { Component } from "react";
import StackTrace from "stacktrace-js";

window.onerror = function(msg, file, line, col, error) {
  StackTrace.fromError(error).then(err => {
    StackTrace.report(
      err,
      `//${window.location.hostname}:${process.env.REACT_APP_LOGGER_PORT || 3334}/jsnlog.logger`,
      {
        type: "window.onerror",
        url: window.location.href,
        userId: window.userId,
        agent: window.navigator.userAgent,
        date: new Date(),
        msg: msg
      }
    );
  });
};

class ErrorBoundary extends Component {
  constructor(props) {
    super(props);
    this.state = { error: null };
  }

  componentDidCatch(error, errorInfo) {
    this.setState({ error });
    StackTrace.fromError(error).then(err => {
      StackTrace.report(
        err,
        `//${window.location.hostname}:${process.env.REACT_APP_LOGGER_PORT || 3334}/jsnlog.logger`,
        {
          type: "React boundary",
          url: window.location.href,
          userId: window.userId,
          agent: window.navigator.userAgent,
          date: new Date(),
          msg: error.toString()
        }
      );
    });
  }

  render() {
    if (this.state.error) {
      //render fallback UI
      return (
        <div className="snap text-center">
          <p>We're sorry — something's gone wrong.</p>
          <p>Our team has been notified</p>
        </div>
      );
    } else {
      //when there's not an error, render children untouched
      return this.props.children;
    }
  }
}

export default ErrorBoundary;
于 2018-06-15T17:42:12.740 回答
3

首先,创建源映射很重要。我通过在 webpack 配置中添加devtools来创建源映射来做到这一点。它的简短片段如下:

devtools: "source-map",
new UglifyJsPlugin({
  sourceMap: true
})

创建源映射后,我使用了库https://www.stacktracejs.com/

但是,为了减少生产中的包大小,我没有导入整个堆栈跟踪包。我通过分离客户端代码和服务器端来实现。

客户端:我导入了 error-stack-parser。这将创建一个对象,其中包含文件名、行号、列号和函数名。我将使用它创建的对象发送到服务器。

import ErrorStackParser from "error-stack-parser";

componentDidCatch(error) {
   let params = {stackframes: ErrorStackParser.parse(error)};
   let url = 'https://example.com';
   axios.post(url, params)
}

在服务器端,我导入了“stacktrace-gps”“stackframe”并使用它来查找它,以从源映射中获取实际代码的行号和列。

const StackTraceGPS = require("stacktrace-gps");
const request = require("request");

var logger = function(req, res) {
  let stackframes = req.body.stackframes;
  let stackframe = new StackFrame(
    stackframes[0]
  ); /* Getting stack of the topmost element as it contains the most important information */

  /* We send extra ajax function to fetch source maps from url */
  const gps = new StackTraceGPS({
    ajax: url => {
      return new Promise((resolve, reject) => {
        request(
          {
            url,
            method: "get"
          },
          (error, response) => {
            if (error) {
              reject(error);
            } else {
              resolve(response.body);
            }
          }
        );
      });
    }
  });

  gps.pinpoint(stackframe).then(
    info => {
      console.log(info); /* Actual file Info*/
    },
    err => {
      console.log(err);
    }
  );
};

这减少了包的大小,并使您能够在服务器端记录错误。

于 2018-10-30T15:45:27.583 回答