php - PHP 测试，用于程序代码

Question

有什么方法可以测试程序代码吗？我一直在研究 PHPUnit，这似乎是一种创建自动化测试的好方法。但是，它似乎面向面向对象的代码，是否有任何替代程序代码的方法？

或者我应该在尝试测试网站之前将网站转换为面向对象？这可能需要一段时间，这有点问题，因为我没有太多时间可以浪费。

谢谢，

丹尼尔。

Answer 1

You can test procedural code with PHPUnit. Unit tests are not tied to object-oriented programming. They test units of code. In OO, a unit of code is a method. In procedural PHP, I guess it's a whole script (file).

While OO code is easier to maintain and to test, that doesn't mean procedural PHP cannot be tested.

Per example, you have this script:

simple_add.php

$arg1 = $_GET['arg1'];
$arg2 = $_GET['arg2'];
$return = (int)$arg1 + (int)$arg2;
echo $return;

You could test it like this:

class testSimple_add extends PHPUnit_Framework_TestCase {

    private function _execute(array $params = array()) {
        $_GET = $params;
        ob_start();
        include 'simple_add.php';
        return ob_get_clean();
    }

    public function testSomething() {
        $args = array('arg1'=>30, 'arg2'=>12);
        $this->assertEquals(42, $this->_execute($args)); // passes

        $args = array('arg1'=>-30, 'arg2'=>40);
        $this->assertEquals(10, $this->_execute($args)); // passes

        $args = array('arg1'=>-30);
        $this->assertEquals(10, $this->_execute($args)); // fails
    }

}

For this example, I've declared an _execute method that accepts an array of GET parameters, capture the output and return it, instead of including and capturing over and over. I then compare the output using the regular assertions methods from PHPUnit.

Of course, the third assertion will fail (depends on error_reporting though), because the tested script will give an Undefined index error.

Of course, when testing, you should put error_reporting to E_ALL | E_STRICT.