8

我有 Animal 协议，其中包含 2 个符合它的结构和一个存储 Animals 列表的 Farm 结构。然后，我使它们都符合 Codable 以将其存储在文件中，但它会引发错误cannot automatically synthesize 'Encodable' because '[Animal]' does not conform to 'Encodable'

我理解为什么会发生这种情况，但我找不到好的解决方案。如何使数组仅接受 Codable 和 Animal，而不将 Animal 标记为 Codable，这样就不会发生此问题，例如var animals = [Codable & Animal]？（或任何其他解决方法）。谢谢

protocol Animal: Codable {
    var name: String { get set }
    var sound: String { get set }
}

struct Cow: Animal {
    var name = "Cow"
    var sound = "Moo!"
}

struct Duck: Animal {
    var name = "Duck"
    var sound = "Quack!"
}

struct Farm: Codable {

    var name = "Manor Farm"
    // this is where the error is shown
    var animals = [Animal]()

}

--edit-- 当我将它们更改为一个类时，它看起来像这样：

class Animal: Codable {
    var name = ""
    var sound = ""
}

class Duck: Animal {
    var beakLength: Int

    init(beakLength: Int) {
        self.beakLength = beakLength
        super.init()

        name = "Duck"
        sound = "Quack!"
    }

    required init(from decoder: Decoder) throws {
        // works, but now I am required to manually do this?
        fatalError("init(from:) has not been implemented")
    }
}

如果我没有其他属性，它会起作用，但是一旦我添加了一个，我就需要引入一个初始化程序，然后我需要从解码器初始化程序中包含初始化程序，它删除了 Codable 提供的自动转换。因此，要么我为我扩展的每个类手动执行此操作，要么我可以强制转换变量（如var beakLength: Int!）以消除对初始化程序的要求。但是有没有别的办法？这似乎是一个简单的问题，但解决它使它变得非常混乱，我不喜欢。另外，当我使用这种方法从文件中保存/加载时，似乎没有保存数据

4

2 回答 2

6

您可以通过 2 种方式执行此操作：

1 解决方案 - 使用包装器：

protocol Animal {}

struct Cow: Animal, Codable {
}

struct Duck: Animal, Codable {
}

struct Farm: Codable {
    let animals: [Animal]

    private enum CodingKeys: String, CodingKey {
        case animals
    }

    func encode(to encoder: Encoder) throws {
        let wrappers = animals.map { AnimalWrapper($0) }
        var container = encoder.container(keyedBy: CodingKeys.self)
        try container.encode(wrappers, forKey: .animals)
    }

    init(from decoder: Decoder) throws {
        let container = try decoder.container(keyedBy: CodingKeys.self)
        let wrappers = try container.decode([AnimalWrapper].self, forKey: .animals)
        self.animals = wrappers.map { $0.animal }
    }
}

fileprivate struct AnimalWrapper: Codable {
    let animal: Animal

    private enum CodingKeys: String, CodingKey {
        case base, payload
    }

    private enum Base: Int, Codable {
        case cow
        case duck
    }

    init(_ animal: Animal) {
        self.animal = animal
    }

    public init(from decoder: Decoder) throws {
        let container = try decoder.container(keyedBy: CodingKeys.self)
        let base = try container.decode(Base.self, forKey: .base)

        switch base {
            case .cow:
                self.animal = try container.decode(Cow.self, forKey: .payload)
            case .duck:
                self.animal = try container.decode(Duck.self, forKey: .payload)
        }
    }

    public func encode(to encoder: Encoder) throws {
        var container = encoder.container(keyedBy: CodingKeys.self)

        switch animal {
            case let payload as Cow:
                try container.encode(Base.cow, forKey: .base)
                try container.encode(payload, forKey: .payload)
            case let payload as Duck:
                try container.encode(Base.duck, forKey: .base)
                try container.encode(payload, forKey: .payload)
            default:
                break
        }
    }
}

2 解决方案 - 使用枚举

struct Cow: Codable {
}

struct Duck: Codable {
}

enum Animal {
    case cow(Cow)
    case duck(Duck)
}

extension Animal: Codable {
    private enum CodingKeys: String, CodingKey {
        case base, payload
    }

    private enum Base: Int, Codable {
        case cow
        case duck
    }

    init(from decoder: Decoder) throws {
        let container = try decoder.container(keyedBy: CodingKeys.self)
        let base = try container.decode(Base.self, forKey: .base)
        switch base {
            case .cow:
                self = .cow(try container.decode(Cow.self, forKey: .payload))
            case .duck:
                self = .duck(try container.decode(Duck.self, forKey: .payload))
        }
    }

    func encode(to encoder: Encoder) throws {
        var container = encoder.container(keyedBy: CodingKeys.self)
        switch self {
            case .cow(let payload):
                try container.encode(Base.cow, forKey: .base)
                try container.encode(payload, forKey: .payload)
            case .duck(let payload):
                try container.encode(Base.duck, forKey: .base)
                try container.encode(payload, forKey: .payload)
        }
    }
}
于 2020-03-05T16:59:00.870 回答
1

我个人会选择@nightwill 枚举解决方案。这似乎是正确的做法。然而，如果你真的需要编码和解码一些你不拥有的受协议约束的对象，这里有一种方法：

protocol Animal {
    var name: String { get set }
    var sound: String { get set }
    //static var supportedTypes : CodingUserInfoKey { get set }
}

typealias CodableAnimal = Animal & Codable
struct Cow: CodableAnimal  {
    var name = "Cow"
    var sound = "Moo!"
    var numberOfHorns : Int = 2 // custom property
    // if you don't add any custom non optional properties you Cow can easyly be decoded as Duck
}

struct Duck: CodableAnimal {
    var name = "Duck"
    var sound = "Quack!"
    var wingLength: Int = 50 // custom property
}

struct Farm: Codable {
    
    var name  = "Manor Farm"
    var animals = [Animal]()
    
    enum CodingKeys: String, CodingKey {
        case name
        case animals
    }
    func encode(to encoder: Encoder) throws {
        var c = encoder.container(keyedBy: CodingKeys.self)
        try c.encode(name, forKey: .name)
        var aniC = c.nestedUnkeyedContainer(forKey: .animals)
        for a in animals {
            if let duck = a as? Duck {
                try aniC.encode(duck)
            } else if let cow = a as? Cow {
                try aniC.encode(cow)
            }
        }
    }
    
    
    init(from decoder: Decoder) throws {
        let c = try decoder.container(keyedBy: CodingKeys.self)
        name = try c.decode(String.self, forKey: .name)
        var aniC = try c.nestedUnkeyedContainer(forKey: .animals)
        while !aniC.isAtEnd {
            if let duck = try? aniC.decode(Duck.self) {
                animals.append(duck)
            } else if let cow = try? aniC.decode(Cow.self) {
                animals.append(cow)
            }
        }
    }
    
    init(name: String, animals: [Animal]) {
        self.name = name
        self.animals = animals
    }
}

游乐场快速检查：

let farm = Farm(name: "NewFarm", animals: [Cow(), Duck(), Duck(), Duck(name: "Special Duck", sound: "kiya", wingLength: 70)])

print(farm)
import Foundation
let jsonEncoder = JSONEncoder()
jsonEncoder.outputFormatting = .prettyPrinted
let encodedData = try! jsonEncoder.encode(farm)
print(String(data: encodedData, encoding: .utf8)!)
if let decodedFarm = try? JSONDecoder().decode(Farm.self, from: encodedData) {
    print(decodedFarm)
    let encodedData2 = try! jsonEncoder.encode(decodedFarm)
    print(String(data: encodedData2, encoding: .utf8)!)
    assert(encodedData == encodedData2)
} else {
    print ("Failed somehow")
}
于 2020-11-26T15:13:58.763 回答