1

我尝试使用flopy，因此我可以尝试使用 python 和modflow运行一些优化程序。Modflow 需要处理大量数据，我们使用不同的文件提供这些信息。

我们提供输入和软盘运行 modflow

我的麻烦是， flopy 似乎无视输入文件并给出相同的结果，无论我给出什么输入。

这是代码：

nper = 10
class BASreader:
    def __init__(self):
        self.ibound = None
        self.head = None

        with open("inps/bas/ibound", "r") as f:
            data = f.read().replace("-", " -").split()
            data = [int(x) for x in data]
            data = np.array(data).reshape(1, 71, 24)
            self.ibound = data

        with open("inps/bas/head", "r") as f:
            data = f.read().split()
            data = [float(x) for x in data]
            self.head = np.array(data).reshape(1, 71, 24)


class Modflow:
    def __init__(self):
        self.modelname = 'outs/gen1'
        self.mf = flopy.modflow.Modflow(self.modelname, exe_name=r'G:\Program Files (x86)\Visual MODFLOW\mf2005.exe')

        dis = flopy.modflow.ModflowDis.load("inps/yo.dis", self.mf)

        basreader = BASreader()
        bas = flopy.modflow.ModflowBas(self.mf, ibound=basreader.ibound, strt=basreader.head)
        self.prev_headdata = basreader.head

        wel = flopy.modflow.ModflowWel(self.mf, stress_period_data=WellProvider(nper).wells)

        fname = 'inps/yo.evt'
        fhandle = open(fname, 'r')
        packages = []
        ext_unit_dict = {22: flopy.utils.mfreadnam.NamData('EVT', fname, fhandle, packages)}
        evt = flopy.modflow.ModflowEvt.load(fhandle, self.mf, ext_unit_dict=ext_unit_dict)
        fhandle.close()

        rech = {}
        for x in range(nper):
            rech[x] = 1.44e-5
        rch = flopy.modflow.ModflowRch(self.mf, rech=rech)

        stress_period_data = {}
        for kper in range(nper):
            for kstp in range(int(nper/10)):
                stress_period_data[(kper, kstp)] = ['save head',
                                                    'save drawdown',
                                                    'save budget',
                                                    'print head',
                                                    'print drawdown',
                                                    'print budget']
        oc = flopy.modflow.ModflowOc(self.mf, stress_period_data=stress_period_data, compact=True)
        chd = flopy.modflow.ModflowChd.load("inps/yo.chd", self.mf)
        lpf = flopy.modflow.ModflowLpf(self.mf, hk=14.44, vka=14.44, ipakcb=53, sy=0.22)

        self.mf.write_input()

    def run(self):
        success, buff = self.mf.run_model(silent=True)
        headobj = bf.HeadFile(self.modelname + '.hds')
        newheaddata = headobj.get_alldata()[-1][0]
        return newheaddata

    mdflw = Modflow()
    mdflw.run()

现在，即使我更改了 EVT、RCH 或 WEL 信息，结果也是一样的。我什至尝试不包含上述文件，但结果仍然相同。任何指针？

4

1 回答 1

1

脚本的此修订会产生不同的水头结果（因为使用了不同的地下水补给值）。在修改后的示例中，我使用 bcf2ss MODFLOW-2005 输入文件作为基本文件。

由于您的输入文件不可用，因此不完全确定为什么您的脚本无法正常工作。

import os
import numpy as np
import flopy


class BASreader:
    def __init__(self):
        self.ibound = None
        self.head = None

        with open("inps/bas/ibound", "r") as f:
            data = f.read().replace("-", " -").split()
            data = [int(x) for x in data]
            data = np.array(data).reshape(2, 10, 15)
            self.ibound = data

        with open("inps/bas/head", "r") as f:
            data = f.read().split()
            data = [float(x) for x in data]
            self.head = np.array(data).reshape(2, 10, 15)


class Modflow:
    def __init__(self, ws='outs', rech_val=.0040, wel_data=None):
        self.model_ws = ws
        self.modelname = 'gen1'
        self.mf = flopy.modflow.Modflow(self.modelname, exe_name='mf2005',
                                        model_ws=self.model_ws)

        dis = flopy.modflow.ModflowDis.load("inps/yo.dis", self.mf, check=False)
        nper = dis.nper
        nstp = dis.nstp.array

        basreader = BASreader()
        bas = flopy.modflow.ModflowBas(self.mf, ibound=basreader.ibound,
                                       strt=basreader.head)
        self.prev_headdata = basreader.head
        bcf = flopy.modflow.ModflowBcf.load("inps/yo.bc6", self.mf)

        if wel_data is None:
            wel_data = [[1, 2, 3,  -35000.],
                        [1, 7, 3,  -35000.]]
        wel_spd = {1: wel_data}

        wel = flopy.modflow.ModflowWel(self.mf,
                                       stress_period_data=wel_spd)

        riv = flopy.modflow.ModflowRiv.load('inps/yo.riv', self.mf, check=False)

        rech = {}
        for x in range(nper):
            rech[x] = rech_val
        rch = flopy.modflow.ModflowRch(self.mf, rech=rech)

        pcg = flopy.modflow.ModflowPcg.load('inps/yo.pcg', self.mf)

        stress_period_data = {}
        for kper in range(nper):
            for kstp in range(nstp[kper]):
                stress_period_data[(kper, kstp)] = ['save head',
                                                    'save drawdown',
                                                    'save budget',
                                                    'print head',
                                                    'print drawdown',
                                                    'print budget']
        oc = flopy.modflow.ModflowOc(self.mf,
                                     stress_period_data=stress_period_data,
                                     compact=True)

        self.mf.write_input()

    def run(self):
        success, buff = self.mf.run_model(silent=True)
        fpth = os.path.join(self.model_ws, self.modelname + '.hds')
        headobj = flopy.utils.HeadFile(fpth)
        newheaddata = headobj.get_data(idx=1)
        return newheaddata


if __name__ == "__main__":
    m1 = Modflow()
    h1 = m1.run()

    m2 = Modflow(rech_val=.0041)
    h2 = m2.run()

    assert np.array_equal(h1, h2), 'h1 does not equal h2'
于 2019-01-08T19:05:41.847 回答