1

我使用此代码向我的 Web 服务器发出 HttpGet 请求。它在模拟器上运行良好，但在我的 HTC Sense 中却不行。执行只是结束而不做任何http请求。任何的想法 ？

File f = new File(user.getPhotopath());
List<NameValuePair> reqparams = new LinkedList<NameValuePair>();
reqparams.add(new BasicNameValuePair("email", user.getEmail()));
reqparams.add(new BasicNameValuePair("pwd", user.getPassword()));
reqparams.add(new BasicNameValuePair("name", user.getScreenName()));
reqparams.add(new BasicNameValuePair("photo", f.getName()));
reqparams.add(new BasicNameValuePair("preference", user.getPrefs()));
reqparams.add(new BasicNameValuePair("bluetoothid", bid));

String urlstring = "http://www.mysite.com/me?"+ URLEncodedUtils.format(reqparams, "utf-8");

try {
    URL url = new URL(urlstring);

URI myURI = null;
try {
    myURI = url.toURI();
} catch (URISyntaxException e) {
                e.printStackTrace();
}
HttpClient httpClient = new DefaultHttpClient();
HttpGet getMethod = new HttpGet(myURI);
HttpResponse webServerResponse = null;
HttpEntity httpEntity = null;
try {
    webServerResponse = httpClient.execute(getMethod);
    httpEntity = webServerResponse.getEntity();
} catch (ClientProtocolException e) {
    e.printStackTrace();
} catch (IOException e) {
    e.printStackTrace();
}
if (httpEntity != null) {

    InputStream instream = httpEntity.getContent();
    BufferedReader reader = new BufferedReader( new InputStreamReader(instream));
    StringBuilder sb = new StringBuilder();
    String line = null;
    try {
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
    } catch (IOException e) {
            e.printStackTrace();
    } finally {
        try {
            resultStr = sb.toString();
            instream.close();
        } catch (IOException e) {
                e.printStackTrace();
        }
    }
4

2 回答 2

0

stacktrace 中没有异常也没有警告。只有内存分配消息。无论如何，我通过使用 URLConnection 而不是 HttpClient 解决了它：

try {
      URL url = new URL(urlstring);
      URLConnection connection = url.openConnection();
      InputStream inputStream = connection.getInputStream();
      BufferedInputStream bufferedInput = new BufferedInputStream(inputStream);

    // Read the response into a byte array
      ByteArrayBuffer byteArray = new ByteArrayBuffer(50);
      int current = 0;
      while((current = bufferedInput.read()) != -1){
            byteArray.append((byte)current);
      }

      // Construct a String object from the byte array containing the response
     resultStr = new String(byteArray.toByteArray());
    } catch (Exception e) {
      e.printStackTrace();
    }

出于某种原因，它起作用了。仍在试图弄清楚出了什么问题。

于 2011-02-21T23:05:40.747 回答
0

虽然您的方法是正确的并且可以工作，但使用EntityUtils帮助器类将响应正文作为字符串检索要容易得多。简单地：

String body = EntityUtils.toString(httpEntity);
于 2011-05-05T23:07:33.050 回答