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我在 Ren'py 6.99.14.3 中愉快地编程，然后我启动了游戏，但出现了错误。我尝试回到游戏在我的脚本中运行的最后一次，但我仍然遇到错误。我尝试调查了一段时间，但我没有丝毫想法（可能是初学者）。

这是“traceback.txt”的第一部分（不是完整的追溯部分）

I'm sorry, but an uncaught exception occurred.

After initialization, but before game start.
  File "game/screens.rpy", line 714, in prepare_screen
    screen preferences():
  File "game/screens.rpy", line 714, in prepare
    screen preferences():
  File "game/screens.rpy", line 718, in prepare
    use game_menu(_("Preferences"), scroll="viewport"):
  File "game/screens.rpy", line 718, in prepare
    use game_menu(_("Preferences"), scroll="viewport"):
  File "game/screens.rpy", line 720, in prepare
    vbox:
  File "game/screens.rpy", line 720, in prepare
    vbox:
  File "game/screens.rpy", line 722, in prepare
    hbox:
  File "game/screens.rpy", line 722, in prepare
    hbox:
  File "game/screens.rpy", line 725, in prepare
    if renpy.variant("pc"):
  File "game/screens.rpy", line 725, in prepare
    if renpy.variant("pc"):
  File "game/screens.rpy", line 727, in prepare
    vbox:
  File "game/screens.rpy", line 727, in prepare
    vbox:
  File "game/screens.rpy", line 730, in prepare
    textbutton _("Window") action Preference("display", "window")
  File "game/screens.rpy", line 730, in prepare
    textbutton _("Window") action Preference("display", "window")
  File "renpy/common/00preferences.rpy", line 454, in Preference
    rv = get()
  File "renpy/common/00preferences.rpy", line 211, in get
    return __DisplayAction(1.0)
  File "renpy/common/00preferences.rpy", line 27, in __init__
    self.width = int(factor * config.screen_width)
Exception: Character expects its what argument to be a string, got 1280.0.

如果您愿意，我会提供更多信息，如果可以的话

谢谢你的帮助！

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1 回答 1

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"Exception: Character expects its what argument to be a string, got 1280.0."

您是否像这样将您的角色之一定义为“int”？

define int = Character ('Name', color="ffffff", show_two_window=True,)

Int 代表整数，它是一种处理数字的编程变量（因此为什么你可能在其中有数字 1280.0，它试图找到一个可以使用的数字）。这是一个保留名称列表，可帮助您再次避免这些错误，或者查看您是否将其命名为您不应该使用的其他名称。

于 2018-04-29T18:37:59.243 回答