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我有一个包含 8 个 tif 文件的 LANDSAT 图像的文件夹。

list.files("C:/Users/Documents/04.HUMEDALES/L5__002072-09MAY-2006",  pattern = glob2rx("*.TIF"),full.names = TRUE)

如图所示：

[1] "C:/Users/Documents/L5__002072-09MAY-2006/LT05_L1TP_002072_20060509_20161121_01_T1_B1.TIF" 
[2] "C:/Users/Documents/L5__002072-09MAY-2006/LT05_L1TP_002072_20060509_20161121_01_T1_B2.TIF" 
[3] "C:/Users/Documents/L5__002072-09MAY-2006/LT05_L1TP_002072_20060509_20161121_01_T1_B3.TIF" 
[4] "C:/Users/Documents/L5__002072-09MAY-2006/LT05_L1TP_002072_20060509_20161121_01_T1_B4.TIF" 
[5] "C:/Users/Documents/L5__002072-09MAY-2006/LT05_L1TP_002072_20060509_20161121_01_T1_B5.TIF" 
[6] "C:/Users/Documents/L5__002072-09MAY-2006/LT05_L1TP_002072_20060509_20161121_01_T1_B6.TIF" 
[7] "C:/Users/Documents/L5__002072-09MAY-2006/LT05_L1TP_002072_20060509_20161121_01_T1_B7.TIF" 
[8] "C:/Users/Documents/L5__002072-09MAY-2006/LT05_L1TP_002072_20060509_20161121_01_T1_BQA.TIF"

如何仅列出波段 1 到 5 和 7 的 tif 文件？我找不到合适的模式。这是我得到的最接近的（仅删除最后一个文件：BQA.tif）

list.files("C:/Users/Documents/04.HUMEDALES/L5__002072-09MAY-2006", pattern = glob2rx("*B?.TIF"), full.names = TRUE)
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1 回答 1

3

从这组文件中：

> list.files(".")
 [1] "bar-foo_B1.tif"  "bar-foo_B2.tif"  "bar-foo_B3.tif"  "bar-foo_B4.tif" 
 [5] "bar-foo_B5.tif"  "bar-foo_B6.tif"  "bar-foo_B7.tif"  "bar-foo_BQA.tif"
 [9] "foo_B1.tif"      "foo_B2.tif"      "foo_B3.tif"      "foo_B4.tif"     
[13] "foo_B5.tif"      "foo_B6.tif"      "foo_B7.tif"      "foo_BQA.tif"

我可以选择使用此正则表达式，它匹配任何 (.*)、B、1 到 5 和 7，然后是“.tif”，然后是文件名的结尾：

> list.files(".",pattern=".*B[123457]\\.tif$", ignore.case=TRUE)
 [1] "bar-foo_B1.tif" "bar-foo_B2.tif" "bar-foo_B3.tif" "bar-foo_B4.tif"
 [5] "bar-foo_B5.tif" "bar-foo_B7.tif" "foo_B1.tif"     "foo_B2.tif"    
 [9] "foo_B3.tif"     "foo_B4.tif"     "foo_B5.tif"     "foo_B7.tif"
于 2018-04-20T16:03:49.330 回答