2

我使用以下代码为每个 ID 分配年份 2017,2018,2019,2020：

proc sort data=Have;
    by ID;
    run;

data Have2;
    set Have(keep=id);
    by id ;
    if first.id then do Vintage= 2017 to 2020;
    output;
    end;
run;

proc sort data=have2;
by id;
run;

data have3 ;
    merge have2 have;
    by id;
run;

这样数据集看起来像这样：

data have3;
input ID Vintage;
datalines;
1 2017
1 2018
1 2019
1 2020
2 2017
2 2018
2 2019
2 2020  
3 2017
3 2018
3 2019
3 2020
4 2017
4 2018
4 2019
4 2020 
;
run;

现在的问题是我正在处理一个看起来像这样的数据集

data newdata;
input ID Type;
datalines;
1 A
1 A
1 A
1 A
1 L
1 L
1 L
1 L
2 A
2 A
2 A
2 A
2 L
2 L
2 L
2 L
;
run;

现在Vintage附加在2017,2018,2019,2020,2020,2020,2020

有没有一种方法可以通过 ID 和类型附加到年份，使上面的数据看起来像这样 

data want;
input ID Type Vintage;
datalines;
1 A 2017
1 A 2018
1 A 2019
1 A 2020
1 L 2017
1 L 2018
1 L 2019
1 L 2020
2 A 2017
2 A 2018
2 A 2019
2 A 2020
2 L 2017
2 L 2018
2 L 2019
2 L 2020
;
run;

TIA

4

3 回答 3

3 
data want;
set newdata;
by id Type;
if first.Type then vintage=2017;
  else vintage+1;
run;
于 2018-04-20T13:50:53.867 回答
2

因为您要进行一堆交叉连接，所以只需为每列创建具有不同值的表，然后在 PROC SQL 中将它们连接在一起

data ids;
input ID ;
datalines;
1
2
3
4
;
run;

data vintages;
input vintage ;
datalines;
2017
2018
2019
2020
;
run;

data types;
input type $;
datalines;
A
L
;
run;

proc sql noprint;
create table have3 as 
select a.id, b.type
from ids a, types b;

create table want as
select a.id, b.type, c.vintage
from ids a, types b, vintages c
order by id, type, vintage;
quit;
于 2018-04-20T14:16:24.700 回答
1

vintage你可以用和idfor做同样的事情type

data want;
set have3;
by id vintage;

if first.vintage then do;
    do type="A","L";
        output;
    end;
end;
run;

proc sort data=want;
by id type vintage;
run;

SQL 解决方案将需要一个 DISTINCT 子句来删除重复项。这是因为交叉连接将创建重复记录，因为newdata有重复。

proc sql noprint;
create table want as
select a.id, b.type, a.vintage
    from have3 as a,
         (select distinct * from newdata) as b
    where a.id = b.id
    order by a.id, b.type, a.vintage;
quit;
于 2018-04-20T13:22:20.273 回答