mysql - 带条件的mysql group_contact

Question

我认为这很少见，不确定是否可行。

我有这个查询：

$sql = "SELECT id_product,GROUP_CONCAT(id_tag  ORDER BY id_tag  ) AS producto  
FROM ps_product_tag  
where id_product = '194'
GROUP BY id_product";

我得到了这个结果：

Array ( [id_product] => 194 [producto] => 36,190,273,274,275,276,277,278,279,280,281,282,284,286,287,289 ) 

我需要做的是对具有多个 where 条件的 id_tag 结果数组进行一些过滤。

WHERE t.`id_tag` = '275'
AND t.`id_tag` = '282'
AND t.`id_tag` = '286'
AND t.`id_tag` = '289'

但我做不到。

谁能帮助我。

Answer 1

您可以添加这样的HAVING子句：

SELECT
    id_product,
    GROUP_CONCAT(id_tag ORDER BY id_tag) AS producto,
    COUNT(*) as `n`
FROM ps_product_tag
WHERE id_tag IN ('275', '282', '286', '287')
GROUP BY id_product
HAVING `n`=4

Answer 2

假设这(id_product, id_tag)是独一无二的，试试这个：

SELECT id_product
FROM ps_product_tag
WHERE id_tag IN ('275', '282', '286', '287')
GROUP BY id_product
HAVING COUNT(id_tag) = 4

Answer 3

如果您需要带有四个标签的产品，您可以使用：

SELECT
      p.id_product,
      GROUP_CONCAT(p.id_tag ORDER BY id_tag) AS producto,
  FROM ps_product_tag as p INNER JOIN 
   (SELECT id_product  
      FROM ps_product_tag
      WHERE id_tag IN ('275', '282', '286', '287')
    GROUP BY id_product HAVING COUNT(*) = 4) as alltags
    ON alltags.id_product = p.id_product
GROUP BY id_product