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我正在尝试使用 AWS Database Migration Service (DMS) 从 S3 填充 SQL Server 2014 表。我有以下 S3 架构：

{
  "TableCount": "1",
  "Tables": [
    {
      "TableName": "employee",
      "TablePath": "public/employee/",
      "TableOwner": "",
      "TableColumns": [
        {
          "ColumnName": "Id",
          "ColumnType": "INT8",
          "ColumnNullable": "false",
          "ColumnIsPk": "true"
        },
        {
          "ColumnName": "HireDate",
          "ColumnType": "TIMESTAMP"
        },
        {
          "ColumnName": "Name",
          "ColumnType": "STRING",
          "ColumnLength": "20"
        }
      ],
      "TableColumnsTotal": "3"
    }
  ]
}

当我运行迁移任务时，我收到以下溢出错误，因为 SQL Server 不允许将2018-04-11 08:02:16.788027S3 中的值插入到 SQL ServerDATETIME列中。

我的问题是，有没有一种方法可以告诉 AWS DMS在 SQL Server 中将TIMESTAMPS3 数据创建为DATETIME2列？注意：每次迁移运行时，都会删除并重新创建表。我可以通过使用 HireDate as 在 SQL-Server 中手动创建表来解决此问题DATETIME2，然后将 DMS 迁移“目标表准备模式”设置为TRUNCATE而不是删除/创建，但这对于我当前的解决方案来说并不理想。

[TARGET_LOAD ]E: Failed to execute statement: 'INSERT INTO [public].[employee]([Id],[HireDate],[Name]) values (?,?,?)' [1022502] (ar_odbc_stmt.c:2456)
[TARGET_LOAD ]E: RetCode: SQL_ERROR SqlState: 22008 NativeError: 0 Message: [Microsoft][ODBC Driver 13 for SQL Server]Datetime field overflow. Fractional second precision exceeds the scale specified in the parameter binding. Line: 1 Column: 4 [1022502] (ar_odbc_stmt.c:2462)
[TARGET_LOAD ]E: Invalid input for column 'HireDate' of table 'public'.'employee' in line number 1.(sqlserver_endpoint_imp.c:2357)
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1 回答 1

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"ColumnScale"解决方案是在 S3 架构中为列指定属性timestamp，这将确保 SQL Server 目标列创建为DATETIME2(7)ie

{
  "TableCount": "1",
  "Tables": [
    {
      "TableName": "employee",
      "TablePath": "public/employee/",
      "TableOwner": "",
      "TableColumns": [
        {
          "ColumnName": "Id",
          "ColumnType": "INT8",
          "ColumnNullable": "false",
          "ColumnIsPk": "true"
        },
        {
          "ColumnName": "HireDate",
          "ColumnType": "TIMESTAMP",
          "ColumnScale": "7",
        },
        {
          "ColumnName": "Name",
          "ColumnType": "STRING",
          "ColumnLength": "20"
        }
      ],
      "TableColumnsTotal": "3"
    }
  ]
}
于 2018-04-19T09:47:31.467 回答