我正在尝试从一组大部分独立的模块中构建一个 uber-jar,但它并没有像我想象的那样工作。
我最初被引导到这里:https ://maven.apache.org/plugins/maven-assembly-plugin/examples/multimodule/module-binary-inclusion-simple.html虽然现在我不太确定这就是我应该从...开始
父 pom 文件如下所示:
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.mycompany</groupId>
<artifactId>BigProject</artifactId>
<version>0.0.1</version>
<packaging>pom</packaging>
<name>BigProject</name>
<modules>
<module>../mod1</module>
<module>../mod2</module>
<!-- ...a bunch more... -->
<module>../distribution</module>
</modules>
<build>
<pluginManagement>
<plugins>
<!-- not even sure why this needs to be specified here, but the documentation seems to think it's important... -->
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<version>3.1.0</version>
<configuration>
<descriptors>
<descriptor>src/assembly/assembly.xml</descriptor>
</descriptors>
</configuration>
</plugin>
</plugins>
</pluginManagement>
</build>
</project>
“分发”模块的 pom 如下所示:
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<artifactId>distribution</artifactId>
<name>distribution</name>
<packaging>pom</packaging>
<parent>
<groupId>com.mycompany</groupId>
<artifactId>BigProject</artifactId>
<version>0.0.1</version>
</parent>
<build>
<plugins>
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<version>3.1.0</version>
<executions>
<execution>
<id>distro-assembly</id>
<phase>package</phase>
<goals>
<goal>single</goal>
</goals>
<configuration>
<descriptors>
<descriptor>src/assembly/assembly.xml</descriptor>
</descriptors>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
</build>
</project>
最后,汇编文件:
<assembly xmlns="http://maven.apache.org/ASSEMBLY/2.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/ASSEMBLY/2.0.0 http://maven.apache.org/xsd/assembly-2.0.0.xsd">
<id>bin</id>
<formats>
<format>dir</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<moduleSets>
<moduleSet>
<includeSubModules>true</includeSubModules>
<useAllReactorProjects>true</useAllReactorProjects>
<includes>
<include>com.myCompany:mod1</include>
<include>com.myCompany:mod2</include>
<!-- and others... -->
</includes>
<binaries>
<includeDependencies>true</includeDependencies>
<outputDirectory>modules/maven-assembly-plugin</outputDirectory>
<unpack>false</unpack>
</binaries>
</moduleSet>
</moduleSets>
</assembly>
(我意识到在某些时候我可能需要更改<format>dir</format>
为,<format>jar</format>
但现在,我只想让一些工作正常)
当我mvn clean package
从主父模块的目录运行时,我收到如下警告:
[INFO] 读取程序集描述符:src/assembly/assembly.xml [警告] 在此工件包含过滤器中从未触发以下模式: o'com.myCompany:mod1' o'com.myCompany:mod2' ...
其次是错误:
[错误] 无法在项目分发中执行目标 org.apache.maven.plugins:maven-assembly-plugin:3.1.0:single (distro-assembly):创建程序集失败:创建程序集存档 bin 时出错:存档不能为空-> [帮助 1]
我真正想要的:
一个 jar 文件包含我的所有模块及其所有依赖项(即 *-with-dependencies.jars),作为一个包含所有内容的 jar 文件。
我真的不确定如何在多模块环境中实现这一点。