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BGP 日志文件：bgplog.log

Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.65: the number of BGP UPDATE messages received changed from '110376' to '110393'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.93: the number of BGP UPDATE messages received changed from '133736' to '134146'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.65: the number of BGP UPDATE messages sent changed from '108252' to '108348'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.93: the number of BGP UPDATE messages sent changed from '2094' to '2132'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.103: the number of BGP UPDATE messages sent changed from '91440' to '91462'
Host local.domain.net [11.130.55.2] with interface to BGP peer eth1-local.domain.net [11.8.44.10]: the number of BGP UPDATE messages sent changed from '1411' to '1413'
Host local.domain.net [11.130.55.2] with interface to BGP peer 10.81.244.18: the number of BGP UPDATE messages sent changed from '112347' to '112506'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.65: the number of messages received from the remote peer changed from '538672' to '538691'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.93: the number of messages received from the remote peer changed from '547397' to '547814'

客观的：

  1. 查找特定 IP，比如说：11.130.44.93
  2. 任何行与上面的 IP 匹配，拆分行并将某些值存储到每个键。
  3. 对密钥进行排序

这是我尝试过的代码：似乎我被卡住了

import re
import os


def find(line):
    findThis = ""
    found = re.match(r'.*?11.130.44.103.*', line)
    # Find is true:
    if found:
        # found a item and adds in to findThis
        findThis = found.group()
    else:
        findThis = "NONE"
    return findThis


def generateDicts(log):
    currentDict = {}
    for line in log:
        if line.startswith(find(line)):
            currentDict = {
                "host": line.split(" ")[1][:24],
                "ip": line.split(" ", 9)[2],
                "peer": line.split(" ")[8],
                "info": line.split(" ", 9)[-1]}
        else:
            # currentDict = {"info":line.split("-",6)[-1]}
            currentDict = line


with open("bgplog.txt") as f:
    print list(generateDicts(f))

我只得到最后一个值，不知何故它没有附加。最好的方法是什么？

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2 回答 2

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我猜你想要一个生成器，在这种情况下你需要使用yield关键字。试试这个：

def generateDicts(log):
    for line in log:
        if line.startswith(find(line)):
            yield {
                "host": line.split(" ")[1][:24],
                "ip": line.split(" ", 9)[2],
                "peer": line.split(" ")[8],
                "info": line.split(" ", 9)[-1]}
于 2018-04-06T20:27:58.427 回答
0

一种方法可能是将字典附加到列表中。如果没有必要，不要使用正则表达式......

with open("bgplog.txt") as log:
    ip_to_search = '11.130.55.2'
    result = []

    for log_line in log:
        if ip_to_search in log_line:
            currentDict = {
                "host": log_line.split(" ")[1][:24],
                "ip": log_line.split(" ", 9)[2],
                "peer": log_line.split(" ")[8],
                "info": log_line.split(" ", 9)[-1]}
            result.append(currentDict)

    for element in result:
        print(element)
于 2018-04-06T20:48:01.003 回答