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所以我不得不说我是使用 PowerShell 解析 XML 的新手。话虽如此，我该如何组合多个 -XPath 以便我可以完成构建我的表达式报告。请让我知道，我已经尝试了几种组合，但它们似乎都不适用于命名空间 XML。

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" niaVersion="12.0.0.756" xmlns="http://something.com/something/hotfix/manifest">
    <releases>
        <release name="mid November 2017">
            <hotfixes>
                <hotfixref name="DE002" description="" defectSuite="n/a" supportEscalation="n/a" internalNotes="" customer="n/a">
                    <packages>
                        <package type="All" />
                    </packages>
                    <components>
                        <component type="" />
                        <component type="" />
                    </components>
                </hotfixref>
                <hotfixref name="DE5728" description="" defectSuite="DS001" supportEscalation="n/a" internalNotes="" customer="n/a">
                    <packages>
                        <package type="Full" />
                    </packages>
                    <components>
                        <component type="" />
                    </components>
                </hotfixref>
            </hotfixes>
        </release>
    </releases>
</manifest>




[xml]$xdoc=Get-Content $PSScriptRoot\Manifest.xml
$ns = @{test ="http://something.com/something/hotfix/manifest"}
$ver = Select-Xml -Xml $xdoc -XPath '//test:release' -Namespace $ns 
$hfu = Select-Xml -Xml $xdoc -XPath '//test:hotfixref' -Namespace $ns 
foreach ($v in $ver){
$v | Select-Object -ExpandProperty node 
 $hfu |  Select-Object -ExpandProperty node
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1 回答 1

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我不明白为什么您需要同时找到修补程序和发布节点。Release 是 hotfixes 的父节点，因此只需找到所有 release-nodes 并在循环中访问其子节点即可找到相关的 hotfixes。前任：

$xdoc = [xml]@"
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" niaVersion="12.0.0.756" xmlns="http://something.com/something/hotfix/manifest">
    <releases>
        <release name="mid November 2017">
            <hotfixes>
                <hotfixref name="DE002" description="" defectSuite="n/a" supportEscalation="n/a" internalNotes="" customer="n/a">
                    <packages>
                        <package type="All" />
                    </packages>
                    <components>
                        <component type="" />
                        <component type="" />
                    </components>
                </hotfixref>
                <hotfixref name="DE5728" description="" defectSuite="DS001" supportEscalation="n/a" internalNotes="" customer="n/a">
                    <packages>
                        <package type="Full" />
                    </packages>
                    <components>
                        <component type="" />
                    </components>
                </hotfixref>
            </hotfixes>
        </release>
    </releases>
</manifest>
"@



$ns = @{test ="http://something.com/something/hotfix/manifest"}
$releases = Select-Xml -Xml $xdoc -XPath '//test:release' -Namespace $ns  
foreach ($r in $releases){
    "$($r.node.name) contains the following hotfixes:"
    $r.node.hotfixes.hotfixref | Select-Object Name, description, defectSuite
}

输出：

mid November 2017 contains the following hotfixes:

name   description defectSuite
----   ----------- -----------
DE002              n/a
DE5728             DS001

如果您真的希望一个 xpath-query 找到这两种类型，请使用|(OR) 分隔 xpath-queries。前任：

Select-Xml -Xml $xdoc -XPath '//test:release|//test:hotfixref' -Namespace $ns

Node      Path        Pattern
----      ----        -------
release   InputStream //test:release|//test:hotfixref
hotfixref InputStream //test:release|//test:hotfixref
hotfixref InputStream //test:release|//test:hotfixref

这样做的问题是您将需要逻辑来检测您正在访问的节点类型，因为它可能是 release 也可能是hotfixref. 您还需要额外的逻辑来了解哪个hotfixref版本属于哪个版本。

于 2018-03-29T08:49:58.513 回答