3

我正在用python构建一个应用程序。我正在使用sqlalchemy-migrate来跟踪我的数据库模式。我有一个表 user_category，它有两列：id 和 name。我正在尝试使用 user_category 表的外键创建一个用户表。我用于创建用户表的更改脚本如下： 

from sqlalchemy import *
from migrate import *
from migrate.changeset import *

meta = MetaData()
user_category = Table('user_category', meta)

user = Table('user', meta,
    Column('id', Integer, primary_key=True),
    Column('email', String(255)),
    Column('first_name', String(40)),
    Column('surname', String(40)),
    Column('password', String(255)),
    Column('user_category', Integer, ForeignKey("user_category.id")),
)

def upgrade(migrate_engine):
    # Upgrade operations go here. Don't create your own engine; bind migrate_engine
    # to your metadata
    meta.bind = migrate_engine
    user.create()

def downgrade(migrate_engine):
    # Operations to reverse the above upgrade go here.
    meta.bind = migrate_engine
    user.drop()

当我运行“manage.py test”时，我得到了错误： 

sqlalchemy.exc.NoReferencedColumnError: Could not create ForeignKey 'user_catego
ry.id' on table 'user': table 'user_category' has no column named 'id'
4

2 回答 2

5

user_category可以告诉 SQLAlchemy 从数据库中自动加载表结构，而不是复制粘贴表的定义：

from sqlalchemy import *
from migrate import *
from migrate.changeset import *

meta = MetaData()

user = Table('user', meta,
    Column('id', Integer, primary_key=True),
    Column('email', String(255)),
    Column('first_name', String(40)),
    Column('surname', String(40)),
    Column('password', String(255)),
    Column('user_category', Integer, ForeignKey("user_category.id")),
)

def upgrade(migrate_engine):
    _t = sa.Table('user_category', meta, autoload=True)
    meta.bind = migrate_engine
    user.create()

抱歉回复晚了 ：）

于 2012-06-14T03:28:31.637 回答
3

您声称您的“user_category”表具有名称和 ID。“user_category”的定义根本不包含任何列:)

于 2011-02-13T12:30:35.923 回答