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当鼠标按下和释放事件之间没有拖动事件时,我想触发一些动作。换句话说 - 当用户在点击时保持鼠标光标不动。问题具体是关于实现它的直接方式。真的很感激 RxJava2 解决方案(我将它与 RxJavaFx 一起使用)。

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2 回答 2

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Observable.combineLatest(
            JavaFxObservable.eventsOf(panel1, MouseEvent.DRAG_DETECTED).map(event -> System.currentTimeMillis()).startWith(System.currentTimeMillis()),
            JavaFxObservable.eventsOf(panel1, MouseEvent.MOUSE_PRESSED).map(event -> System.currentTimeMillis()),
            JavaFxObservable.eventsOf(panel1, MouseEvent.MOUSE_RELEASED).map(event -> System.currentTimeMillis()),
            (dragDectedMillis, pressedMillis, releasedMillis) -> releasedMillis > pressedMillis && dragDectedMillis < pressedMillis ? true : false)
    .filter(noDragDetected -> noDragDetected)
    .subscribe(next -> System.out.println("Action"));
于 2018-03-21T12:48:32.417 回答
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import io.reactivex.Observable;
import io.reactivex.rxjavafx.observables.JavaFxObservable;
import javafx.application.Application;
import javafx.scene.Scene;
import javafx.scene.input.MouseEvent;
import javafx.scene.layout.StackPane;
import javafx.stage.Stage;

public class PressedReleasedWithoutDraggedApp extends Application {

    public static void main(String[] args) {
        launch(args);
    }

    @Override
    public void start(Stage stage) throws Exception {
        StackPane stackPane = new StackPane();
        stackPane.setPrefSize(800, 600);
        stage.setScene(new Scene(stackPane));
        stage.show();

        Observable<MouseEvent> mousePressedObservable = JavaFxObservable.eventsOf(stackPane, MouseEvent.MOUSE_PRESSED);
        Observable<MouseEvent> mouseReleasedObservable = JavaFxObservable.eventsOf(stackPane, MouseEvent.MOUSE_RELEASED);
        Observable<MouseEvent> mouseDraggedObservable = JavaFxObservable.eventsOf(stackPane, MouseEvent.MOUSE_DRAGGED);

        mousePressedObservable
        .switchMap(mousePressed -> mouseReleasedObservable.takeUntil(mouseDraggedObservable))
        .subscribe(next -> System.out.println("PRESSED'N'RELEASED without DRAGGED"));
    }
}
于 2018-12-07T16:17:03.133 回答