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我真的是个新手，对 Java 脚本也不太熟悉，但我的 Mirth 3.3 源设置为 TCP 侦听器，我收到一条 HL7 ADT 消息。仅当 PID3.1 可用时，我一直在使用类型为规则生成器的源过滤器来处理消息。我想要实现的是，如果消息由于缺少 PID 而被过滤，我想发送带有详细信息“缺少患者 ID”的 AR 消息。我的最终目的地也是 TCP 监听器（不确定这是否重要）

我在全局脚本（后处理）中有以下代码

function setACK(sourceMsg,responseCode,responseMsg,responseStatus) {
    importPackage(com.mirth.connect.model);
    // responseStatus is an optional parameter
    if (!responseStatus)
        responseStatus = {'AA':Response.Status.SUCCESS,'AR':Response.Status.FILTERED,'AE':Response.Status.FAILURE}[responseCode] || Response.Status.UNKNOWN;
    var ack = <HL7Message/>;
    ack.MSH['MSH.1'] = sourceMsg.MSH['MSH.1'].toString();
    ack.MSH['MSH.2'] = sourceMsg.MSH['MSH.2'].toString();
    ack.MSH['MSH.3'] = sourceMsg.MSH['MSH.5'].copy();
    ack.MSH['MSH.4'] = sourceMsg.MSH['MSH.6'].copy();
    ack.MSH['MSH.5'] = sourceMsg.MSH['MSH.3'].copy();
    ack.MSH['MSH.6'] = sourceMsg.MSH['MSH.4'].copy();
    ack.MSH['MSH.7']['MSH.7.1'] = DateUtil.getCurrentDate('yyyyMMddHHmmss');
    ack.MSH['MSH.9']['MSH.9.1'] = sourceMsg.MSH['MSH.9']['MSH.9.1'].toString();
    ack.MSH['MSH.9']['MSH.9.2'] = sourceMsg.MSH['MSH.9']['MSH.9.2'].toString();
    ack.MSH['MSH.9']['MSH.9.3'] = 'ACK';
    ack.MSH['MSH.10'] = sourceMsg.MSH['MSH.10'].copy();
    ack.MSH['MSH.11'] = sourceMsg.MSH['MSH.11'].copy();
    ack.MSH['MSH.12'] = sourceMsg.MSH['MSH.12'].copy();
    ack.MSA['MSA.1']['MSA.1.1'] = responseCode;
    ack.MSA['MSA.2']['MSA.2.1'] = sourceMsg.MSH['MSH.10']['MSH.10.1'].toString();
    ack.MSA['MSA.3']['MSA.3.1'] = responseMsg;
    responseMap.put('ACK',new Response(responseStatus,SerializerFactory.getHL7Serializer().fromXML(ack)));

在源过滤器下，我有带有以下代码的 Javascript 规则

if(msg['PID']['PID.3']['PID.3.1'].toString().length > 0) {
    return true;
}
    setACK(msg,'AR',"MIssing Patient ID.");
return false;

这仍然不起作用我仍然收到一条错误消息进行处理。

4

1 回答 1

0

在接收器通道的Source Transformer中，您可以添加以下内容作为第一步：

var verified = false;

for each (var pid in msg['PID']['PID.3']) {
    if (pid['PID.3.1'].toString()) {
        verified = true;
        break;
    }
}

var ack;
if (verified) {
    ack = ACKGenerator.generateAckResponse(connectorMessage.getRawData(), "AA", "Accepted");
} else {
    ack = ACKGenerator.generateAckResponse(connectorMessage.getRawData(), "AE", "PID.3.1-Patient Identifier is missed");
    destinationSet.removeAll();
}

responseMap.put("ACK", ack);

消息中可能发送了多个 PID。此外，响应可能是AE代码，除非您的个人资料中另有说明。AR保留用于其他类型的验证。此代码段不检查传入消息是否使用增强确认模式。显然，您需要将通道的 Source connector Response 设置为 ACK。

于 2018-03-14T18:11:40.483 回答