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我正在尝试根据他们拥有的评论数量来订购 django 中的项目列表。但是,似乎存在一个问题,即 Count 函数没有考虑到 django 评论也使用 content_type_id 来区分不同对象的评论这一事实!

这给了我一个小问题,因为使用标准方法的所有对象的注释计数都是错误的;是否有“不错”的修复或我需要退回到原始 sql?

尝试和 ge 正确排序的代码:

app_list = App.objects.filter(published=True)
.annotate(num_comments=Count('comments'))
.order_by('-num_comments')

查询的示例输出(注意没有提及内容类型 id):

SELECT "apps_app"."id", "apps_app"."name", 
"apps_app"."description","apps_app"."author_name", "apps_app"."site_url", 
"apps_app"."source_url", "apps_app"."date_added", "apps_app"."date_modified", 
"apps_app"."published", "apps_app"."published_email_sent", "apps_app"."created_by_id", 
"apps_app"."rating_votes", "apps_app"."rating_score", COUNT("django_comments"."id") AS      
"num_comments" FROM "apps_app" LEFT OUTER JOIN "django_comments" ON ("apps_app"."id" = 
"django_comments"."object_pk") WHERE "apps_app"."published" = 1 GROUP BY 
"apps_app"."id", "apps_app"."name", "apps_app"."description", "apps_app"."author_name", 
"apps_app"."site_url", "apps_app"."source_url", "apps_app"."date_added", 
"apps_app"."date_modified", "apps_app"."published", "apps_app"."published_email_sent", 
"apps_app"."created_by_id", "apps_app"."rating_votes", "apps_app"."rating_score" ORDER 
BY num_comments DESC LIMIT 4
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1 回答 1

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认为我找到了答案:Django Snippet

于 2011-02-06T22:45:45.940 回答