我正在尝试将多个 .xls 文件合并到一个工作簿中，其中每个文件都插入到一个以 .xls 文件名命名的工作表中。
在网上冲浪时，我看到了 Pyexcel 的文档和一个特定的模块，如此处所写，可以轻松完成这项工作。这是代码。
from pyexcel.cookbook import merge_all_to_a_book
import glob
merge_all_to_a_book(glob.glob("Dir\*.xls"),"output.xls")
正如预期的那样，它不起作用。这是控制台输出。
File "..\Desktop\scripts\provaimport.py", line 48, in <module>
merge_all_to_a_book(glob.glob("C:\Users\Tesisti\Desktop\forpythonscript\*.xls"),"output.xls")
File "C:\Users\Tesisti\Anaconda2\lib\site-packages\pyexcel\cookbook.py", line 148, in merge_all_to_a_book
merged.save_as(outfilename)
File "C:\Users\Tesisti\Anaconda2\lib\site-packages\pyexcel\internal\meta.py", line 339, in save_as
return save_book(self, file_name=filename, **keywords)
File "C:\Users\Tesisti\Anaconda2\lib\site-packages\pyexcel\internal\core.py", line 51, in save_book
return _save_any(a_source, book)
File "C:\Users\Tesisti\Anaconda2\lib\site-packages\pyexcel\internal\core.py", line 55, in _save_any
a_source.write_data(instance)
File "C:\Users\Tesisti\Anaconda2\lib\site-packages\pyexcel\plugins\sources\file_output.py", line 38, in write_data
**self._keywords)
File "C:\Users\Tesisti\Anaconda2\lib\site-packages\pyexcel\plugins\renderers\excel.py", line 30, in render_book_to_file
save_data(file_name, book.to_dict(), **keywords)
File "C:\Users\Tesisti\Anaconda2\lib\site-packages\pyexcel_io\io.py", line 119, in save_data
**keywords)
File "C:\Users\Tesisti\Anaconda2\lib\site-packages\pyexcel_io\io.py", line 141, in store_data
writer.write(data)
File "C:\Users\Tesisti\Anaconda2\lib\site-packages\pyexcel_io\book.py", line 58, in __exit__
self.close()
File "C:\Users\Tesisti\Anaconda2\lib\site-packages\pyexcel_xls\xlsw.py", line 86, in close
self.work_book.save(self._file_alike_object)
File "C:\Users\Tesisti\Anaconda2\lib\site-packages\xlwt\Workbook.py", line 710, in save
doc.save(filename_or_stream, self.get_biff_data())
File "C:\Users\Tesisti\Anaconda2\lib\site-packages\xlwt\Workbook.py", line 680, in get_biff_data
self.__worksheets[self.__active_sheet].selected = True
关于如何修复的任何想法？