我用 C++ 编写了一个显示星号金字塔的程序（见下文），现在我想看看它是如何在 Python 中完成的，但这并不像我想象的那么容易。
有没有人试过这个，如果是这样，你能告诉我有帮助的代码吗？
提前致谢。
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问问题
50309 次
14 回答
22
def pyramid(rows=8):
for i in range(rows):
print ' '*(rows-i-1) + '*'*(2*i+1)
pyramid(8)
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pyramid(12)
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于 2011-02-06T03:45:22.837 回答
5
或者你可以试试：
def pyramid(size=8):
for i in range(size):
row = '*'*(2*i+1)
print row.center(2*size)
于 2011-02-06T14:20:16.373 回答
3
您可以像这样使用字符串乘法：
>>> for i in range(size):
... print '%s%s'%(' '*(size-(i-1)),'*'*((i*2)-1))
...
于 2011-02-06T03:36:57.887 回答
2
这段代码不是很pythonic，但它是可读的。查看 Hugh Bothewell 对紧凑型金字塔绘图功能的回答：
def drawPyramid(rows):
result = ''
for i in xrange(rows):
row = ''
row += ' ' * (rows - i - 1)
row += '*' * (2 * i + 1)
result += row + '\n'
return result
print drawPyramid(20)
于 2011-02-06T03:50:47.057 回答
2
我建议使用以下功能：
def pyramid(rows=8):
pyramid_width = rows * 2
for asterisks in range(1, pyramid_width, 2):
print("{0:^{1}}".format("*" * asterisks, pyramid_width))
然后尝试：
pyramid()
或与：
pyramid(4)
于 2011-02-06T11:41:10.227 回答
2
如果你喜欢列表推导：
> n = 5
> print("\n".join((i*"*").center(n*2) for i in range(1, n*2, 2)))
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于 2017-12-30T20:43:06.527 回答
1
Pyramid, Inverted Pyramid and Diamond Rhombus in Python:
Pyramid
i=1
j=5
while i<=5:
print((j*' ')+i*'* ')
j=j-1
i=i+1
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* *
* * *
* * * *
* * * * *
Inverted Pyramid
i=1
j=5
while i<=5:
print((i*' ')+j*'* ')
j=j-1
i=i+1
* * * * *
* * * *
* * *
* *
*
Diamond Rhombus
i=1
j=5
while i<=5:
print((j*' ')+i*'* ')
while j<=5 & i==5:
print(((j+1)*' ')+(5-j)*'* ')
j=j+1
j=j-1
i=i+1
*
* *
* * *
* * * *
* * * * *
* * * *
* * *
* *
*
于 2016-09-04T16:26:19.623 回答
1
user_input = input("How many rows do you want to print? \n")
def stars(a):
size = int(a)
for i in range(1, size+1):
print(" "*(size-i),"*"*(i*2-1))
stars(user_input)
How many rows do you want to print?
20
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于 2020-07-02T07:11:59.000 回答
0
$ cat tree.py
def line(n, i):
line = ''
for j in range(n - i - 1):
line += ' '
for j in range(2 * i + 1):
line += '*'
for j in range(n - i - 1):
line += ' '
return line
def tree(n):
for i in range(n):
line_ = line(n, i)
print(line_)
def run():
tree(3)
if __name__ == '__main__':
run()
$ python3 tree.py
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$ _
于 2017-06-21T07:08:19.580 回答
0
n=4
m = (2*n)-2
for i in range(0, m):
for j in range(0, m):
print(end=" ")
m = m - 1 # decrementing m after each loop
for j in range(0, i + 1):
# printing full Triangle pyramid using stars
print("* ", end=' ')
print(" ")
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* *
* * *
于 2019-08-20T04:28:39.873 回答
-1
你也可以画一个钻石
def pyramid(r):
for i in range(r):
print (" "*(r-i-1) + "*"*(2*i+1))
for i in range(r-1,-1,-1):
print (' '*(r-i-1) + "*"*(2*i+1))
n=int(input("Enter no of rows:"))
pyramid(n)
pyramid(10)
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* * *
* * * * *
* * * * * * *
* * * * * * * * *
* * * * * * * * * * *
* * * * * * * * * * * * *
* * * * * * * * * * * * * * *
* * * * * * * * * * * * * * * * *
* * * * * * * * * * * * * * * * * * *
* * * * * * * * * * * * * * * * * * *
* * * * * * * * * * * * * * * * *
* * * * * * * * * * * * * * *
* * * * * * * * * * * * *
* * * * * * * * * * *
* * * * * * * * *
* * * * * * *
* * * * *
* * *
*
>>>
于 2014-03-13T15:10:20.540 回答
-1
def pyramid(row):
for n in range(row):
print(' '*(n+1)+' '*(2*(row-n))+'x'+'x'*(2*n+1))
pyramid(row=8)
于 2016-06-14T21:44:28.873 回答
-1
虽然我对 python 非常陌生，但这是我解决它的方法：
k=int(input("Enter the number of rows"))
for i in range(1,k):
print(' '*(k-i),'* '*(i))
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* * * * *
* * * * * *
* * * * * * *
于 2016-08-09T12:17:13.613 回答
-2
#!/usr/bin/python
for i in range(1,6):
for j in range(1,i+1):
print "*",
print
O/P:
===
*
* *
* * *
* * * *
* * * * *
2)
#!/usr/bin/python
for i in range(1,6):
for j in range(1,7-i):
print "*",
print
O/P:
* * * * *
* * * *
* * *
* *
*
3)
#!/usr/bin/python
for i in range(1,6):
for j in range(1,6-i):
print "",
for k in range(1,i+1):
print "*",
print
O/P:
*
* *
* * *
* * * *
* * * * *
4)
#!/usr/bin/python
for i in range(1,6):
for j in range(1,1+i):
print "",
for k in range(1,7-i):
print "*",
print
O/P:
* * * * *
* * * *
* * *
* *
*
5)
#!/usr/bin/python
for i in range(1,6):
for j in range(1,6-i):
print "",
for k in range(1,i+1):
print "*",
print
for i in range(1,5):
for j in range(1,1+i):
print "",
for k in range(1,6-i):
print "*",
print
O/P:
*
* *
* * *
* * * *
* * * * *
* * * *
* * *
* *
*
于 2016-12-12T07:57:33.930 回答