我想用 T 变量简化这段代码,但无法成功编译。希望你能给我方法。
这是我要重写的“重复”代码:
func getIntegerValue (listValues: [Any], numValueToRead: Int, readValue: inout Int) -> Bool {
if numValueToRead < 0 || numValueToRead >= listValues.count {
return false
}
let value = listValues [numValueToRead]
if type (of: value) == type(of: readValue) {
readValue = value as! Int
return true
} else {
return false
}
}
func getStringValue (listValues: [Any], numValueToRead: Int, readValue: inout String) -> Bool {
if numValueToRead < 0 || numValueToRead >= listValues.count {
return false
}
let value = listValues [numValueToRead]
if type (of: value) == type(of: readValue) {
readValue = value as! String
return true
} else {
return false
}
}
这是我编写但未编译的代码:
func getValue <T> (listValues: [Any], numValueToRead: Int, readValue: inout T) -> Bool {
if numValueToRead < 0 || numValueToRead >= listValues.count {
return false
}
let value = listValues [numValueToRead]
if type (of: value) == type(of: readValue) {
switch value {
case let integerValue as Int:
readValue = integerValue
case let stringValue as String:
readValue = stringValue
default:
return false
}
return true
} else {
return false
}
}
对于那些做作,我得到了那些编译错误: readValue = integerValue -> 'Int' is not convertible to 'T' readValue = stringValue -> 'String' is not convertible to 'T'
有没有办法使用泛型将我的两个函数与一个独特的函数合成?