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我正在尝试使用此代码在处理开始之前强制我的进度视图绘制:

public static class ProgressBehaviors
{
    public static readonly DependencyProperty ForceRepaintProperty =
        DependencyProperty.RegisterAttached(
        "ForceRepaint",
        typeof(bool),
        typeof(ProgressBehaviors),
        new UIPropertyMetadata(false, OnForceRepaintChanged));

    public static bool GetForceRepaint(FrameworkElement treeViewItem)
    {
        return (bool)treeViewItem.GetValue(ForceRepaintProperty);
    }

    public static void SetForceRepaint(FrameworkElement treeViewItem, bool value)
    {
        treeViewItem.SetValue(ForceRepaintProperty, value);
    }

    static void OnForceRepaintChanged(DependencyObject a_object, DependencyPropertyChangedEventArgs e)
    {
        Border item = a_object as Border;
        if (item == null)
            return;

        item.IsVisibleChanged += (s, ev) =>
            {
                item.UpdateLayout();
                Window window = Window.GetWindow(item);
                if (window != null)
                    window.Measure(window.RenderSize);
            };
    }
}

基本行为注入。我必须这样做的原因是,否则请等待进度消息直到完成它必须做的任何事情之后才会显示。我正在尝试UpdateLayoutMeasure但都不起作用。每个人都告诉我,我在 WPF 中做错了事。什么,我应该将我正在执行的每个进程包装在第二个线程或 Dispatcher 调用中吗?这看起来很难看。

4

1 回答 1

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这是一种方法:http ://dedjo.blogspot.com/2007/08/how-to-doevents-in-wpf.html

于 2011-02-04T21:07:39.920 回答