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我正在使用一个views.py 子进程操作系统调用，它以非零返回码失败，我需要捕获问题所在。我还想记录所有内容，并且努力按照说明（https://docs.pylonsproject.org/projects/pyramid/en/latest/narr/logging.html?awesome > Advanced Configuration > 见下文）来完成这项工作.

TIA

金字塔装置是最近建成的

virtualenv --no-site-packages myproj
cd /home/user/myproj/
source bin/activate
pip3.6 install pyramid pyramid-debugtoolbar pyramid-jinja2 waitress cookiecutter
pcreate -s starter mywsgi
cd mywsgi
python3.6 setup.py develop

在运行时保存 production.ini

views.py 调用

import os
import subprocess
import json
from pyramid.view import view_config

@view_config(route_name='overlay_event', renderer='json')
def event_view(request):
    return {'new_overlay': subprocess.check_output(['/usr/bin/foo', '/path/thing.script',json.dumps(request.json_body)])

production.ini 是样板文件，如下所示。我的版本低于此。对于 subprocess.check_output 的非零返回代码失败，我确实获得了控制台日志记录，但没有从失败的脚本调用发送到 STDOUT 和 STDERR 的内容。我的脚本运行良好，所以它一定是某个环境、路径、JSON、ARGV 或其他问题。但我也只想记录。

当我根据上述日志记录指令编辑以下内容时，我收到有关错误处理程序的错误。当我逐渐将我的编辑回滚到 production.ini 时，就会发生这种情况。也许这缺少一些额外的包含或？view.py 也需要改变吗？

生物板

###
# app configuration
# https://docs.pylonsproject.org/projects/pyramid/en/1.9-branch/narr/environment.html
###

[app:main]
use = egg:myproj

pyramid.reload_templates = false
pyramid.debug_authorization = false
pyramid.debug_notfound = false
pyramid.debug_routematch = false
pyramid.default_locale_name = en

###
# wsgi server configuration
###

[server:main]
use = egg:waitress#main
listen = *:6543

###
# logging configuration
# https://docs.pylonsproject.org/projects/pyramid/en/1.9-branch/narr/logging.html
###

[loggers]
keys = root, myproj

[handlers]
keys = console

[formatters]
keys = generic

[logger_root]
level = WARN
handlers = console

[logger_myproj]
level = WARN
handlers =
qualname = myproj

[handler_console]
class = StreamHandler
args = (sys.stderr,)
level = NOTSET
formatter = generic

[formatter_generic]
format = %(asctime)s %(levelname)-5.5s [%(name)s:%(lineno)s][%(threadName)s] %(message)s

我对 production.ini 文件的编辑

[loggers]
keys = root, filelog

[handlers]
keys = console, myproj, filelog

[formatters]
keys = generic

[logger_root]
level = INFO
handlers = console, filelog

[logger_filelog]
class = FileHandler
args = ('%(here)s/myproj.log','a')
level = INFO
formatter = generic

[logger_myproj]
level = WARN
qualname = myproj

[handler_console]
class = StreamHandler
args = (sys.stderr,)
level = NOTSET
formatter = generic

[formatter_generic]
format = %(asctime)s %(levelname)-5.5s [%(name)s:%(lineno)s][%(threadName)s] %(message)s
4

1 回答 1

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您应该使用run而不是check_output.

try:
    result = subprocess.run(
        ['/usr/bin/foo', '/path/thing.script', json.dumps(request.json_body)],
        check=True,
        stdout=subprocess.PIPE,
        stderr=subprocess.STDOUT,
    )
except subprocess.CalledProcessError as ex:
    output = ex.stdout.decode('utf-8')
    log.error('Call to /usr/bin/foo failed: %s', output)

此外，我会警惕request.json_body直接传递到命令行，以防可能的注入攻击。

于 2018-02-27T15:15:53.117 回答