json - XML到JSON角度4

Question

我使用了一个 api，它以 XML（以下格式）而不是 JSON 给出结果。

<soapenv:Envelope >
   <soapenv:Header/>
   <soapenv:Body>
      <p444:DetailsResult>
         <Policy>
            <RenewalEligibility>YES</RenewalEligibility>
            <ContCovBenEligibility>NO</ContCovBenEligibility>
            <Client>
               <FirstName>Pradeep</FirstName>
               <LastName>Chaudhary</LastName>
               <GenderCode>1</GenderCode>
               <SmokerFlag>0</SmokerFlag>
               <MaritalStatusCode>0</MaritalStatusCode>
            </Client>
         </Policy>
         <WebAdress xsi:nil="true"/>
      </p444:PolicyDetailsResult>
   </soapenv:Body>
</soapenv:Envelope>

我使用像这样的 xmlToJson 方法将上述 xml 转换为 JSON。

让 jsonText = JSON.stringify(this.xmlToJson(xml)); 让 jsoParseData = JSON.parse(jsonText);

我得到了以下格式的结果。

{
  "soapenv:Envelope": {
    "soapenv:Body": {
      "p444:DetailsResult": {
        "Policy": {
          "RenewalEligibility": "YES",
          "ContCovBenEligibility": "NO",
          "Client": {
            "FirstName": "Pradeep",
            "LastName": "Chaudhary",
            "GenderCode": "1",
            "SmokerFlag": "0",
            "MaritalStatusCode": "0"
          }
        }
      }
    }
  }
}

但我想以以下格式提取到 JSON

"Header": null,
   "Body": {
      "PolicyDetailsResult": {
         "Policy": {
            "RenewalEligibility": "YES",
            "ContCovBenEligibility": "NO",
            "Client":{
               "FirstName":"Pradeep",
               "LastName":"Chaudhary",
               "GenderCode":"1",
               "SmokerFlag":"0",
               "MaritalStatusCode":"0",
            }      
        }
     }
   }

提前致谢