使用 Symfony 3.4,我需要在注销之前持久化用户,所以我实现了以下监听器:
<?php
namespace c975L\UserBundle\Listeners;
use Doctrine\ORM\EntityManagerInterface;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\Security\Core\Authentication\Token\TokenInterface;
use Symfony\Component\Security\Http\Logout\LogoutHandlerInterface;
use c975L\UserBundle\Entity\User;
class LogoutListener implements LogoutHandlerInterface
{
private $em;
public function __construct(EntityManagerInterface $em)
{
$this->em = $em;
}
public function logout(Request $request, Response $response, TokenInterface $token)
{
$user = $token->getUser();
if ($user instanceof User) {
$user->setLatestSignout(new \DateTime());
$this->em->persist($user);
$this->em->flush();
}
}
}
我已经自动接线services.yml
services:
_defaults:
autowire: true
autoconfigure: true
public: true
c975L\UserBundle\Listeners\:
resource: '../../Listeners/*'
但我收到以下编译错误
编译错误:ContainerNxlf3ac\appDevDebugProjectContainer::load(): 无法打开所需的 '/.../var/cache/dev/ContainerNxlf3ac/getLogoutlistener2Service.php' (include_path='.:/usr/share/php')
看起来我必须为服务起别名,但我不能这样做......
使用时我有相同的结果parent::__construct();
__construct()
如果已删除但$this->em
未定义,则不会出现错误...
[编辑 - 添加防火墙部分]
security.yml
firewalls:
dev:
pattern: ^/(_(profiler|wdt)|css|fonts|images|js)/
security: false
main:
pattern: ^/
provider: c975_l_userbundle
form_login:
login_path: user_signin
check_path: user_signin
default_target_path: user_dashboard
csrf_token_generator: security.csrf.token_manager
remember_me:
secret: '%secret%'
lifetime: 31536000
path: /
secure: true
anonymous: true
logout_on_user_change: true
logout:
path: user_signout
handlers: [c975L\UserBundle\Listeners\Logoutlistener]