12

我需要发送什么意图来打开我之前在我的应用中创建的通知通道的设置?我需要它从我的设置活动中链接。

4

3 回答 3

34

要打开单个通道的设置,您可以使用ACTION_CHANNEL_NOTIFICATION_SETTINGS

Intent intent = new Intent(Settings.ACTION_CHANNEL_NOTIFICATION_SETTINGS)
        .putExtra(Settings.EXTRA_APP_PACKAGE, context.getPackageName())
        .putExtra(Settings.EXTRA_CHANNEL_ID, yourChannelId);
startActivity(intent);

使用ACTION_APP_NOTIFICATION_SETTINGS将列出应用程序的所有频道:

Intent intent = new Intent(Settings.ACTION_APP_NOTIFICATION_SETTINGS)
        .putExtra(Settings.EXTRA_APP_PACKAGE, context.getPackageName());
startActivity(intent);
于 2018-02-18T16:55:11.033 回答
14

这里是通知设置的片段以及精细的频道设置:

private void openNotificationSettings() {
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
        Intent intent = new Intent(Settings.ACTION_APP_NOTIFICATION_SETTINGS);
        intent.putExtra(Settings.EXTRA_APP_PACKAGE, getPackageName());
        startActivity(intent);
    } else {
        Intent intent = new Intent(Settings.ACTION_APPLICATION_DETAILS_SETTINGS);
        intent.setData(Uri.parse("package:" + getPackageName()));
        startActivity(intent);
    }
}

@RequiresApi(26)
private void openChannelSettings(String channelId) {
    Intent intent = new Intent(Settings.ACTION_CHANNEL_NOTIFICATION_SETTINGS);
    intent.putExtra(Settings.EXTRA_APP_PACKAGE, getPackageName());
    intent.putExtra(Settings.EXTRA_CHANNEL_ID, channelId);
    startActivity(intent);
}
于 2018-09-09T11:17:01.733 回答
5

Kotlin 代码,支持比 Android O更早的版本和Lollipop的边缘案例:

fun openAppNotificationSettings(context: Context) {
    val intent = Intent().apply {
        when {
            Build.VERSION.SDK_INT >= Build.VERSION_CODES.O -> {
                action = Settings.ACTION_APP_NOTIFICATION_SETTINGS
                putExtra(Settings.EXTRA_APP_PACKAGE, context.packageName)
            }
            Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP -> {
                action = "android.settings.APP_NOTIFICATION_SETTINGS"
                putExtra("app_package", context.packageName)
                putExtra("app_uid", context.applicationInfo.uid)
            }
            else -> {
                action = Settings.ACTION_APPLICATION_DETAILS_SETTINGS
                addCategory(Intent.CATEGORY_DEFAULT)
                data = Uri.parse("package:" + context.packageName)
            }
        }
    }

    context.startActivity(intent)
}
于 2020-05-25T08:27:04.277 回答