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我使用 SimpleXML 将一个简单的 POJO 保存到 XML 文件中,然后将其读回。我遵循教程。该文件已成功创建,但读取部分根本不起作用。它引发了第二个异常,它来自serializer.read.

Room room = new Room("1");

Serializer serializer = new Persister();
try {
    File ff = new File("room.xml");
    serializer.write(room, ff);
} catch (FileNotFoundException e) {
    System.out.println("FileNotFoundException\n");
} catch (Exception e) {
    System.out.println("Exception from serializer.write\n");
}

try {
    File ffi = new File("room.xml");
    Room aroom = serializer.read(Room.class, ffi);
    System.out.println("RoomName: " + aroom.getRid() + "\n");
} catch (FileNotFoundException e) {
    System.out.println("FileNotFoundException\n");
} catch (Exception e) {
    System.out.println("Exception from serializer.read\n");
}

有什么提示吗?

4

1 回答 1

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确保您在Room.

public Room(){
}

或者,确保您的构造函数如下所示:

public Room(@Attribute(name="rid") String rid){
    this.rid = rid;
}
于 2011-02-03T09:07:39.810 回答