这个满足我的要求。DAG 每分钟运行一次,而我的“主要”任务持续 90 秒,因此它应该跳过每秒钟运行一次。我用 aShortCircuitOperator
检查当前运行是否是目前唯一的运行(在dbdag_run
表中查询),并禁用回填。但是我不能正确地使用which 应该做类似的事情。airflow
catchup=False
LatestOnlyOperator
DAG 文件
import os
import sys
from datetime import datetime
import airflow
from airflow import DAG
from airflow.operators.python_operator import PythonOperator, ShortCircuitOperator
import foo
import util
default_args = {
'owner': 'airflow',
'depends_on_past': True,
'start_date': datetime(2018, 2, 13), # or any date in the past
'email': ['services@mydomain.com'],
'email_on_failure': True}
dag = DAG(
'test90_dag',
default_args=default_args,
schedule_interval='* * * * *',
catchup=False)
condition_task = ShortCircuitOperator(
task_id='skip_check',
python_callable=util.is_latest_active_dagrun,
provide_context=True,
dag=dag)
py_task = PythonOperator(
task_id="test90_task",
python_callable=foo.bar,
provide_context=True,
dag=dag)
airflow.utils.helpers.chain(condition_task, py_task)
实用程序.py
import logging
from datetime import datetime
from airflow.hooks.postgres_hook import PostgresHook
def get_num_active_dagruns(dag_id, conn_id='airflow_db'):
# for this you have to set this value in the airflow db
airflow_db = PostgresHook(postgres_conn_id=conn_id)
conn = airflow_db.get_conn()
cursor = conn.cursor()
sql = "select count(*) from public.dag_run where dag_id = '{dag_id}' and state in ('running', 'queued', 'up_for_retry')".format(dag_id=dag_id)
cursor.execute(sql)
num_active_dagruns = cursor.fetchone()[0]
return num_active_dagruns
def is_latest_active_dagrun(**kwargs):
num_active_dagruns = get_num_active_dagruns(dag_id=kwargs['dag'].dag_id)
return (num_active_dagruns == 1)
foo.py
import datetime
import time
def bar(*args, **kwargs):
t = datetime.datetime.now()
execution_date = str(kwargs['execution_date'])
with open("/home/airflow/test.log", "a") as myfile:
myfile.write(execution_date + ' - ' + str(t) + '\n')
time.sleep(90)
with open("/home/airflow/test.log", "a") as myfile:
myfile.write(execution_date + ' - ' + str(t) + ' +90\n')
return 'bar: ok'
致谢:此答案基于此博客文章。