我正在尝试对 2 个进程进行严格的交替,但我不确定如何声明关键区域和非关键区域。这是我拥有的代码:
#include <iostream>
#include <pthread.h>
int count;
int turn = 0; // Shared variable used to implement strict alternation
void* myFunction(void* arg)
{
int actual_arg = *((int*) arg);
for(unsigned int i = 0; i < 10; ++i) {
while(1)
{
while(turn != 0)
{
critical_region_0();
turn = 1;
non_critical_region_0();
}
}
// Beginning of the critical region
count++;
std::cout << "Thread #" << actual_arg << " count = " << count <<
std::endl;
// End of the critical region
while(0)
{
while(turn != 1)
{
critical_region_1();
turn = 0
non_critical_region_1();
}
}
}
pthread_exit(NULL);
}
int main()
{
int rc[2];
pthread_t ids[2];
int args[2];
count = 0;
for(unsigned int i = 0; i < 2; ++i) {
args[i] = i;
rc[i] = pthread_create(&ids[i], NULL, myFunction, (void*) &args[i]);
}
for(unsigned int i = 0; i < 2; ++i) {
pthread_join(ids[i], NULL);
}
std::cout << "Final count = " << count << std::endl;
pthread_exit(NULL);
}
我知道关键区域和非关键区域的编写方式好像它们是一种方法,但我将它们用作占位符。有没有办法在不使用这些方法的情况下进行严格交替?
这是输出的样子。
Thread #0 count = 1
Thread #1 count = 2
Thread #0 count = 3
Thread #1 count = 4
Thread #0 count = 5
Thread #1 count = 6
Thread #0 count = 7
Thread #1 count = 8
Thread #0 count = 9
Thread #1 count = 10
Thread #0 count = 11
Thread #1 count = 12
Thread #0 count = 13
Thread #1 count = 14
Thread #0 count = 15
Thread #1 count = 16
Thread #0 count = 17
Thread #1 count = 18
Thread #0 count = 19
Thread #1 count = 20
Final count = 20
我只能设法得到的输出首先是线程 1,然后是线程 0。