下面是我试图实现我的用例的链接中的示例代码。在此表中,我将多一列作为第一列,它是一个复选框。选择“编辑”按钮时,只有表格中选定的复选框行应显示可编辑模式,其他行应显示为静态文本。有没有可能实现。任何人都可以帮助我满足我的要求。
<h4>Angular-xeditable Editable row (Bootstrap 3)</h4>
<div ng-app="app" ng-controller="Ctrl">
<table class="table table-bordered table-hover table-condensed">
<tr style="font-weight: bold">
<td style="width:35%">Name</td>
<td style="width:20%">Status</td>
<td style="width:20%">Group</td>
<td style="width:25%">Edit</td>
</tr>
<tr ng-repeat="user in users">
<td>
<!-- editable username (text with validation) -->
<span editable-text="user.name" e-name="name" e-form="rowform" e-ng-hide="true" onbeforesave="checkName($data, user.id)" e-required>
<span ng-hide="false">hello</span>
{{ user.name || 'empty' }}
</span>
</td>
<td>
<!-- editable status (select-local) -->
<span editable-select="user.status" e-name="status" e-form="rowform" e-ng-options="s.value as s.text for s in statuses">
{{ showStatus(user) }}
</span>
</td>
<td>
<!-- editable group (select-remote) -->
<span editable-select="user.group" e-name="group" onshow="loadGroups()" e-form="rowform" e-ng-options="g.id as g.text for g in groups">
{{ showGroup(user) }}
</span>
</td>
<td style="white-space: nowrap">
<!-- form -->
<form editable-form name="rowform" onbeforesave="saveUser($data, user.id)" ng-show="rowform.$visible" class="form-buttons form-inline" shown="inserted == user">
<button type="submit" ng-disabled="rowform.$waiting" class="btn btn-primary">
save
</button>
<button type="button" ng-disabled="rowform.$waiting" ng-click="rowform.$cancel()" class="btn btn-default">
cancel
</button>
</form>
<div class="buttons" ng-show="!rowform.$visible">
<button class="btn btn-primary" ng-click="rowform.$show()">edit</button>
<button class="btn btn-danger" ng-click="removeUser($index)">del</button>
</div>
</td>
</tr>
</table>
<button class="btn btn-default" ng-click="addUser()">Add row</button>
</div>