php - 如何通过在 PHP 中的同一键中搜索不同数组中的值来找到和数组的值

Question

我的数组$json看起来像这样：

 Array ( 
       [0] => Array ( [poulecode] => 495271
                      [teamcode] => 277986
                      [teamnaam] => JO19-1 (0225 Onder 19 competitie (najaar)) )
       [1] => Array ( [poulecode] => 500027
                      [teamcode] => 277986
                      [teamnaam] => JO19-1 (B3200 Zwaluwen jeugdbeker Onder 19 poule) )
       [2] => Array ( [poulecode] => 524572
                      [teamcode] => 277986
                      [teamnaam] => JO19-1 (0227 Onder 19 competitie (voorjaar)) ) 
       )

如何通过搜索包含某个字符串“voorjaar”$competitiecode来从关联中挑选（设置变量） ？poulecode (524572)teamnaam's ( JO19-1 (0227 Onder 19 competitie (voorjaar)) )

我一直在研究这个使用array_filter，array_column但我似乎无法弄清楚。

到目前为止，这是我的一段代码：

$json = json_decode($content_programma, true);

$Poulecode = array_column($json, 'poulecode');
$Teamnaam = array_column($json, 'teamnaam');
$findme = 'voorjaar';
$key = array_filter($findme, array_column($json, $Teamnaam));
$competitiecode = $Poulecode[$key];

Answer 1

您可以使用foreach循环：

$find = Array();
$search = 'voorjaar';

foreach($json as $j) {
    if (strpos($j['teamnaam'], $search) !== false) {
        $find[] = Array(
            'poulecode' =>  $j['poulecode']
        );
    }
}

Answer 2

<?php
    $array = [
        [
            "poulecode" => 495271,
            "teamcode" => 277986,
            "teamnaam" => "JO19-1 (0225 Onder 19 competitie (najaar)) )"
        ], [
            "poulecode" => 500027,
            "teamcode" => 277986,
            "teamnaam" => "JO19-1 (B3200 Zwaluwen jeugdbeker Onder 19 poule) )"
        ], [
            "poulecode" => 524572,
            "teamcode" => 277986,
            "teamnaam" => "JO19-1 (0227 Onder 19 competitie (voorjaar)) )"
        ]
    ];

    $keyword = "voorjaar";

    // You can filter your array using array_filter function
    $result = array_filter( $array, function( $item ) use ( $keyword ) {
        return strpos( $item['teamnaam'], $keyword ) !== false;
    });

    // and then map result to your datastructure
    $result_ids = array_map( function($item){
        return $item['poulecode'];
    }, $result  );

    var_dump($result_ids);

Answer 3

你array_filter()应该得到这个论点：

$keys = array_filter(array_column($json, $Teamnaam), function($item) use ($findme){
    if (strpos($item['teamnaam'], $findme) !== false) {
        return true;
    }
    return false;
});

$keys现在是一个数组。