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我无法使用 Highcharter 在 R 中重新创建此答案,以将条形图中的条形变为可点击的 URL。这是答案中的Javascript代码。Highcharter 有一个关于我试图遵循的重新创建 Javascript的小插曲。这是迄今为止尝试过的。它没有显示任何条形图。

library(tidyverse)
library(highcharter)

highchart() %>%
  hc_chart(type = "column") %>%
  hc_title(text = "Click points to go to URL") %>%
  hc_xAxis(type = "category") %>%
  hc_plotOptions(series = list(cursor = "pointer"),
                 point =
                   list(events = list(
                     click = JS(
                       "function () {
                       location.href = 'https://en.wikipedia.org/wiki/' +
                       this.options.key;
                       }"
                     )
                     ))) %>%
  hc_series(
    list(name = "USA", key = "United_States", y = 29.9),
    list(name = "Canada", key = "Canada", y = 71.5),
    list(name = "Mexico", key = "Mexico", y = 106.4)
  )
4

1 回答 1

2

安德鲁,

复制示例时您有一些 (2) 错误:

  1. 如果你仔细检查你给出的例子。point论点存在于论点的cursor同一深度series
  2. 您没有以正确的方式添加数据(如小插曲)。

您的代码的固定版本是:

highchart() %>%
  hc_chart(type = "column") %>%
  hc_title(text = "Click points to go to URL") %>%
  hc_xAxis(type = "category") %>%
  hc_plotOptions(
    series = list(
      cursor = "pointer",
      point = list(
        events = list(
          click = JS( "function () { location.href = 'https://en.wikipedia.org/wiki/' + this.options.key; }")
          )
        )
      )
    ) %>%
  hc_series(
    list(
      data = list(
        list(name = "USA", key = "United_States", y = 29.9),
        list(name = "Canada", key = "Canada", y = 71.5),
        list(name = "Mexico", key = "Mexico", y = 106.4)
        )
      )
  )

添加数据的更好版本是:

dat <- data.frame(
  country = c("USA", "Canada", "Mexico"),
  url = c("United_States", "Canada", "Mexico"),
  value = c(29.9, 71.5, 106.4)
)

highchart() %>%
  hc_xAxis(type = "category") %>%
  hc_plotOptions(
    series = list(
      cursor = "pointer",
      point = list(
        events = list(
          click = JS( "function () { location.href = 'https://en.wikipedia.org/wiki/' + this.options.key; }")
          )
        )
      )
    ) %>%
  hc_add_series(data = dat, type = "column", mapping = hcaes(name = country, key = url, y = value))

希望它有帮助

于 2018-01-19T19:00:07.790 回答