7

我的表中有一个 nvarchar(1000) 字段，我在该列中存储 JSON 数据。

例如：

 CONTENT_RULE_ID    CONTENT_RULE
 1                  {"EntityType":"Inquiry", "Values":[1,2]}
 2                  {"EntityType":"Inquiry", "Values":[1,3]}
 3                  {"EntityType":"Inquiry", "Values":[2,4]}
 4                  {"EntityType":"Inquiry", "Values":[5,6,1]}
 6                  {"EntityType":"Inquiry", "Values":[8,1]}
 8                  {"EntityType":"Inquiry", "Values":[10,12,11]}

从此我如何在sql server中使用JSON_QUERY获取所有查询ID为1的CONTENT_RULE_ID

4

4 回答 4

4 
SELECT c.*
FROM CONTENT_RULES AS c
CROSS APPLY OPENJSON(JSON_QUERY(content_rule, '$')) AS x 
CROSS APPLY OPENJSON(x.[Value], '$') AS y
where x.[key]='Values' and y.[value]=1
于 2018-01-12T11:24:02.787 回答
2

@Harisyam，您能否尝试以下查询

declare @val int = 1

;with cte as (
    select *
    from CONTENT_RULES
    cross apply openjson (CONTENT_RULE, '$')
), list as (
    select 
    CONTENT_RULE_ID, replace(replace([value],'[',''),']','') as [value]
    from cte 
    where CONTENT_RULE_ID in (
    select CONTENT_RULE_ID
    from cte 
    where [key] = 'EntityType' and [value] = 'Inquiry'
    ) 
    and [key] = 'Values'
)
select 
CONTENT_RULE_ID, s.value
from list
cross apply string_split([value],',') s
where s.value = @val

我使用SQL string_split函数一一获取查询值

输出是

在此处输入图像描述

第二个查询可以跟随一个

select
    CONTENT_RULE_ID
from CONTENT_RULES
cross apply openjson (CONTENT_RULE, '$')
where replace(replace(value,'[',','),']',',') like '%,1,%'

也许最完整的需要 OpenJSON 支持的 SQL 查询如下

select
    content_rule_id,
    [value]
from Content as c
cross apply openjson(c.CONTENT_RULE, '$') with (
    EntityType nvarchar(100),
    [Values] nvarchar(max) as json
) as e
cross apply openjson([Values], '$') as v
于 2018-01-12T10:41:20.420 回答
1

我的情况类似，但我的不是整数数组，而是复杂类型的数组。这是我基于David Browne 解决方案的代码

SELECT *
FROM TableName AS T
WHERE EXISTS
(
    SELECT *
    FROM OPENJSON(T.JsonColumn, '$.Details')
    WITH
    (
        OrderNumber VARCHAR(200) '$.OrderNumber',
        Quantity INT '$.Quantity'
    )
    WHERE OrderNumber = '1234567'
);

在你的情况下：

SELECT C.*
FROM CONTENT_RULES AS C
WHERE EXISTS
(
    SELECT *
    FROM OPENJSON(C.CONTENT_RULE, '$.Values')
    WHERE value = 1
);
于 2021-10-27T05:46:16.050 回答
0

sql server 2016 可以打开 JSON。

尝试这个：

SELECT c.content_rule_ID, y.[key], y.[value]
  FROM content_rules AS c
  CROSS APPLY OPENJSON(JSON_QUERY(content_rule, '$.content_rule')) AS x
  CROSS APPLY OPENJSON(x.[Values], '$') AS y
  where y.[value] = 1
    and x.[EntityType] = 'Inquiry';
于 2018-01-12T10:47:16.930 回答