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我是 SQWRL 的新手,我必须添加一条新规则。我知道如何执行查询。
我添加新规则的查询是:
"pizza:Pizza(?p) ^ pizza:hasDiameter(?p, ?d) ^ swrlb:greaterThan(?d, 30) -> pizza:BigPizza(?p)"
但我有一个错误:无效的 SWRL atom predicate 'pizza:BigPizza'。而且我不知道如何解决它,因为 BigPizza 是新规则。
:)