3

我有一个简单的Person类，getName()它返回 a String：

public class Person {

    public String getName() {...}

}

如何在运行时LambdaMetafactory为该非静态方法创建 lambda getName()？

这是我到目前为止得到的：

public class MyMain {

    public static void main(String[] args) throws Throwable {
        GetterFunction getterFunction;

        MethodHandles.Lookup lookup = MethodHandles.lookup();
        String invokedMethodName = "getName";
        MethodType invokedType = MethodType.methodType(GetterFunction.class);
        MethodType methodType = MethodType.methodType(Object.class);
        MethodHandle virtual = lookup.findVirtual(Person.class, "getName", MethodType.methodType(String.class));
        CallSite site = LambdaMetafactory.metafactory(lookup,
                invokedMethodName,
                invokedType,
                methodType,
                virtual,
                methodType);
        getterFunction = (GetterFunction) site.getTarget().invokeExact();
        System.out.println(getterFunction.getName(new Person("Ann")));
    }

    @FunctionalInterface
    private interface GetterFunction {

        String getName(Person person);

    }

}

哪个抛出：

java.lang.invoke.LambdaConversionException: Incorrect number of parameters for instance method invokeVirtual foo.Person.getName:()String; 0 captured parameters, 0 functional interface method parameters, 0 implementation parameters
    at java.lang.invoke.AbstractValidatingLambdaMetafactory.validateMetafactoryArgs(AbstractValidatingLambdaMetafactory.java:193)
    at java.lang.invoke.LambdaMetafactory.metafactory(LambdaMetafactory.java:303)
4

2 回答 2

2

这有效：

public class MyMain {

    public static void main(String[] args) throws Throwable {
        GetterFunction getterFunction;
        final MethodHandles.Lookup lookup = MethodHandles.lookup();
        MethodType methodType = MethodType.methodType(String.class, Person.class);
        final CallSite site = LambdaMetafactory.metafactory(lookup,
                "invoke",
                MethodType.methodType(GetterFunction.class),
                methodType,
                lookup.findVirtual(Person.class, "getName", MethodType.methodType(String.class)),
                methodType);
        getterFunction = (GetterFunction) site.getTarget().invokeExact();
        System.out.println(getterFunction.invoke(new Person("Ann")));
    }

    @FunctionalInterface
    interface GetterFunction {

        String invoke(final Person callable);
    }

}
于 2018-01-11T09:34:03.753 回答
2

只是扩展 Geoffrey De Smet 的答案，以展示 Function 的样子，因为需要进行细微的调整：

public class MyMain {

    public static void main(String[] args) throws Throwable {
        MethodHandles.Lookup lookup = MethodHandles.lookup();
        CallSite site = LambdaMetafactory.metafactory(lookup,
                "apply",
                MethodType.methodType(Function.class),
                MethodType.methodType(Object.class, Object.class), // Function::apply signature
                lookup.findVirtual(Person.class, "getName", MethodType.methodType(String.class)),
                MethodType.methodType(String.class, Person.class) // Person::getName signature
        );

        Function<Person, String> getterFunction = (Function<Person, String>) site.getTarget().invokeExact();

        System.out.println(getterFunction.apply(new Person("Ann")));
    }

    static class Person {
        String name;

        public Person(String name) {
            this.name = name;
        }

        public String getName() {
            return name;
        }
    }

}
于 2019-03-09T19:20:37.950 回答