7

我对 Python 还很陌生，我正在使用 Lynda 上的视频教程来帮助我构建社交 WebApp 的框架。我正在尝试使用 cmdpython manage.py runserver从 cmd 运行服务器，但是，我一直遇到此错误消息。

CMD 提示错误

Traceback (most recent call last):

File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\utils\autoreload.py", line 225, in wrapper
    fn(*args, **kwargs)
  File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\core\management\commands\runserver.py", line 121, in inner_run
    self.check(display_num_errors=True)
  File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\core\management\base.py", line 364, in check
    include_deployment_checks=include_deployment_checks,
  File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\core\management\base.py", line 351, in _run_checks
    return checks.run_checks(**kwargs)
  File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\core\checks\registry.py", line 73, in run_checks
    new_errors = check(app_configs=app_configs)
  File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\core\checks\urls.py", line 40, in check_url_namespaces_unique
    all_namespaces = _load_all_namespaces(resolver)
  File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\core\checks\urls.py", line 57, in _load_all_namespaces
    url_patterns = getattr(resolver, 'url_patterns', [])
  File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\utils\functional.py", line 36, in __get__
    res = instance.__dict__[self.name] = self.func(instance)
  File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\urls\resolvers.py", line 536, in url_patterns
    patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)
  File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\utils\functional.py", line 36, in __get__
    res = instance.__dict__[self.name] = self.func(instance)
  File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\urls\resolvers.py", line 529, in urlconf_module
    return import_module(self.urlconf_name)
  File "C:\Users\Kelechi\AppData\Local\Programs\Python\Python35\lib\importlib\__init__.py", line 126, in import_module
    return _bootstrap._gcd_import(name[level:], package, level)
  File "<frozen importlib._bootstrap>", line 986, in _gcd_import
  File "<frozen importlib._bootstrap>", line 969, in _find_and_load
  File "<frozen importlib._bootstrap>", line 958, in _find_and_load_unlocked
  File "<frozen importlib._bootstrap>", line 673, in _load_unlocked
  File "<frozen importlib._bootstrap_external>", line 665, in exec_module
  File "<frozen importlib._bootstrap>", line 222, in _call_with_frames_removed
  File "C:\Windows\SysWOW64\bookmarks\bookmarks\urls.py", line 20, in <module>
    url(r'^admin/', include(admin.site.urls)),
  File "C:\Users\Kelechi\AppData\Roaming\Python\Python35\site-packages\django\urls\conf.py", line 27, in include
    'provide the namespace argument to include() instead.' % len(arg)
django.core.exceptions.ImproperlyConfigured: Passing a 3-tuple to include() is not supported. Pass a 2-tuple containing the list of patterns and app_name, and provide the namespace argument to include() instead.

我的 urls.py 看起来像这样：

from django.contrib import admin

urlpatterns = [
    url(r'^admin/', include(admin.site.urls)),
    ...
]
4

2 回答 2

11

在 Django 2.0 中，您不能再使用include(admin.site.urls)（发行说明）。改用就好admin.site.urls了。

from django.contrib import admin

urlpatterns = [
    url(r'^admin/', admin.site.urls),
    ...
]
于 2018-01-11T09:53:42.567 回答
-1

从 Django 2.0 版开始，文档清除了这一点：

何时使用include()

include()当您包含其他 URL 模式时，您应该始终使用。admin.site.urls是唯一的例外。

于 2021-02-14T15:50:07.927 回答