2

要加入表,我使用以下查询。

SELECT *
FROM(select user as uservalue1 FROM [projectname.FullData_Edited]) as FullData_Edited 
JOIN (select user as uservalue2 FROM [projectname.InstallDate]) as InstallDate 
ON FullData_Edited.uservalue1=InstallDate.uservalue2;

查询有效,但连接表只有两列 uservalue1 和 uservalue2。我想保留两个表中的所有列。知道如何实现吗?

4

2 回答 2

6
#legacySQL
SELECT <list of fields to output>
FROM [projectname:datasetname.FullData_Edited] AS FullData_Edited
JOIN [projectname:datasetname.InstallDate] AS InstallDate
ON FullData_Edited.user = InstallDate.user

或(最好)

#standardSQL
SELECT <list of fields to output>
FROM `projectname.datasetname.FullData_Edited` AS FullData_Edited
JOIN `projectname.datasetname.InstallDate` AS InstallDate
ON FullData_Edited.user = InstallDate.user

请注意,SELECT *在这种情况下使用会导致Ambiguous column name错误,因此最好在输出中明确列出您需要的列/字段

解决方法是使用USING()如下示例中的语法。
假设这user是唯一模棱两可的领域 - 它可以解决问题

#standardSQL
SELECT *
FROM `projectname.datasetname.FullData_Edited` AS FullData_Edited
JOIN `projectname.datasetname.InstallDate` AS InstallDate
USING (user)

例如:

#standardSQL
WITH `projectname.datasetname.FullData_Edited` AS (
  SELECT 1 user, 'a' field1
),
`projectname.datasetname.InstallDate` AS (
  SELECT 1 user, 'b' field2
)
SELECT *
FROM `projectname.datasetname.FullData_Edited` AS FullData_Edited
JOIN `projectname.datasetname.InstallDate` AS InstallDate
USING (user)

返回

user    field1  field2   
1       a       b    

而使用ON FullData_Edited.user = InstallDate.user给出以下错误

Error: Duplicate column names in the result are not supported. Found duplicate(s): user

于 2018-01-09T19:52:51.953 回答
1

如果您想要所有列,请不要使用子查询:

SELECT *
FROM [projectname.FullData_Edited] as FullData_Edited JOIN
     [projectname.InstallDate] as InstallDate 
     ON FullData_Edited.uservalue1 = InstallDate.uservalue2;

您可能必须列出要避免列名重复的特定列。

当您使用它时,您还应该切换到标准 SQL。

于 2018-01-09T19:44:17.330 回答