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我想在AppRTCMobile中添加一个接口，这个接口可以启动webrtc Call模块，以实现两部手机之间的音频通话（局域网，已经知道IP地址和端口号），但是当我运行成功时，软件当 RtcEventLog 调用该方法时，每次发生异常时都会崩溃。我不知道Calling Call是否合理。在没有解决方案的情况下，我真诚地感谢您的帮助。下面是源代码，请帮我找出问题所在。

    std::unique_ptr<RtcEventLog> event_log = webrtc::RtcEventLog::Create();
    webrtc::Call::Config callConfig = webrtc::Call::Config(event_log.get());
    callConfig.bitrate_config.max_bitrate_bps = 500*1000;
    callConfig.bitrate_config.min_bitrate_bps = 100*1000;
    callConfig.bitrate_config.start_bitrate_bps = 250*1000;

    webrtc::AudioState::Config audio_state_config = webrtc::AudioState::Config();
    cricket::VoEWrapper* g_voe  = nullptr;
    rtc::scoped_refptr<webrtc::AudioDecoderFactory> g_audioDecoderFactory;
    g_audioDecoderFactory = webrtc::CreateBuiltinAudioDecoderFactory();
    g_voe = new cricket::VoEWrapper();
    audio_state_config.audio_processing = webrtc::AudioProcessing::Create();
    g_voe->base()->Init(NULL,audio_state_config.audio_processing,g_audioDecoderFactory);
    audio_state_config.voice_engine = g_voe->engine();

    audio_state_config.audio_mixer = webrtc::AudioMixerImpl::Create();
    callConfig.audio_state = AudioState::Create(audio_state_config);
    std::unique_ptr<RtcEventLog> event_logg = webrtc::RtcEventLog::Create();
    callConfig.event_log = event_logg.get();
    g_call = webrtc::Call::Create(callConfig);



    g_audioSendTransport = new AudioLoopbackTransport();
    webrtc::AudioSendStream::Config config(g_audioSendTransport);
    g_audioSendChannelId = g_voe->base()->CreateChannel();
    config.voe_channel_id = g_audioSendChannelId;
    g_audioSendStream = g_call->CreateAudioSendStream(config);


    webrtc::AudioReceiveStream::Config AudioReceiveConfig;
    AudioReceiveConfig.decoder_factory = g_audioDecoderFactory;
    g_audioReceiveChannelId = g_voe->base()->CreateChannel();
    AudioReceiveConfig.voe_channel_id = g_audioReceiveChannelId;
    g_audioReceiveStream = g_call->CreateAudioReceiveStream(AudioReceiveConfig);

    g_audioSendStream->Start();
    g_audioReceiveStream->Start();

这是崩溃发生时发生的错误的屏幕截图。如果您想了解更多，请告诉我。

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1 回答 1

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您的代码在 event_log_->LogAudioPlayout() 处崩溃...显然 event_log_ 对象已被释放。

由 unique_ptr 或 scoped_refptr 管理的对象将在执行后释放，但这些对象可能仍会在您的情况下使用，这将导致崩溃问题。所以把这些对象放在全局内存中或者保留它们。

于 2018-01-12T07:19:01.843 回答