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在斐济 (ImageJ) 我打开了两个图像(Img1 和 Img2)。我想运行一个添加两个图像并将结果存储在 Img1 中的脚本。我打算在一系列图像中执行此操作,因此我想尽量避免创建和关闭许多图像。

这可能吗?我尝试了下面的代码,但是当我Sum3and50.show()在第一次AddSlice()调用后调用第二个时它崩溃了。基本上我很想能够Sum3and50+=imp[Slice]

from __future__ import division
from ij import IJ
from ij import plugin
import time

def AddSlice(Stack,SumImg,Slice):
    Stack.setSlice(Slice)
    ic = plugin.ImageCalculator()
    SliceImg = ic.run("Copy create", Stack, Stack)
    SliceImg.show()
    time.sleep(SLEEP_TIME)  
    SumImg=ic.run("Add RGB", SumImg, SliceImg)
    return SumImg

SLEEP_TIME=1 #seconds    

#imp = IJ.getImage()
imp = IJ.openImage("http://imagej.nih.gov/ij/images/flybrain.zip");
W,H,NCh,NSl,NFr = imp.getDimensions()
imp.show()
Sum3and50 = IJ.createImage("Sum3and50", "RGB black", W, H, 1)
Sum3and50.show()
time.sleep(SLEEP_TIME)  

Sum3and50 = AddSlice(imp,Sum3and50,3)
Sum3and50.show()
time.sleep(SLEEP_TIME)  

Sum3and50 = AddSlice(imp,Sum3and50,5)
Sum3and50.show()
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1 回答 1

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为了避免弹出窗口,我倾向于避免使用插件并ImageProcessor直接使用。这样的函数采用覆盖第一个输入的两个图像的每个像素对的总和如下所示:

def pixel_pair_sum(pro1, pro2):
    for x in range(pro1.getWidth()):
        for y in range(pro1.getHeight()):
            v1 = pro1.get(x, y)
            v2 = pro2.get(x, y)    
            pro1.set(x, y, v1 + v2)

pro1并且pro1ImageProcessors [1]。ImagePlus所以在调用上面的函数之前,你需要先从前面获取它们:

...
sum3and50 = IJ.createImage("Sum3and50", "RGB black", W, H, 1)
p1 = sum3and50.getProcessor()

stk = imp.getStack()

p2 = stk.getProcessor(1) # get the processor for the first slice [2]
pixel_pair_sum(p1, p2) # add the pixel values of slice 1 to sum3and50

p2 = stk.getProcessor(2) # add another slice to sum3and50
pixel_pair_sum(p1, p2)
...
sum3and50.show()

供参考:https
://imagej.nih.gov/ij/developer/api/ij/ImageStack.html [1] https://imagej.nih.gov/ij/developer/api/ij/process/ImageProcessor.html
[2] 另见:https ://imagej.nih.gov/ij/developer/api/ij/ImagePlus.html#setPositionWithoutUpdate-int-int-int-

于 2018-01-04T19:37:45.307 回答