我准备了一个简单的SQL Fiddle来演示我的问题 -
在一个两人游戏中,我将用户聊天存储在一个表中:
CREATE TABLE chat(
gid integer, /* game id */
uid integer, /* user id */
created timestamptz,
msg text
);
在这里,我用一个简单的测试数据填充表格:
INSERT INTO chat(gid, uid, created, msg) VALUES
(10, 1, NOW() + interval '1 min', 'msg 1'),
(10, 2, NOW() + interval '2 min', 'msg 2'),
(10, 1, NOW() + interval '3 min', 'msg 3'),
(10, 2, NOW() + interval '4 min', 'msg 4'),
(10, 1, NOW() + interval '5 min', 'msg 5'),
(10, 2, NOW() + interval '6 min', 'msg 6'),
(20, 3, NOW() + interval '7 min', 'msg 7'),
(20, 4, NOW() + interval '8 min', 'msg 8'),
(20, 4, NOW() + interval '9 min', 'msg 9');
我可以通过运行 SELECT 查询来获取数据:
SELECT ARRAY_TO_JSON(
COALESCE(ARRAY_AGG(ROW_TO_JSON(x)),
array[]::json[])) FROM (
SELECT
gid,
uid,
EXTRACT(EPOCH FROM created)::int AS created,
msg
FROM chat) x;
它返回一个 JSON 数组:
[{"gid":10,"uid":1,"created":1514813043,"msg":"msg 1"},
{"gid":10,"uid":2,"created":1514813103,"msg":"msg 2"},
{"gid":10,"uid":1,"created":1514813163,"msg":"msg 3"},
{"gid":10,"uid":2,"created":1514813223,"msg":"msg 4"},
{"gid":10,"uid":1,"created":1514813283,"msg":"msg 5"},
{"gid":10,"uid":2,"created":1514813343,"msg":"msg 6"},
{"gid":20,"uid":3,"created":1514813403,"msg":"msg 7"},
{"gid":20,"uid":4,"created":1514813463,"msg":"msg 8"},
{"gid":20,"uid":4,"created":1514813523,"msg":"msg 9"}]
这接近我需要的,但是我想使用“gid”作为 JSON 对象属性,其余数据作为该对象中的值:
{"10": [{"uid":1,"created":1514813043,"msg":"msg 1"},
{"uid":2,"created":1514813103,"msg":"msg 2"},
{"uid":1,"created":1514813163,"msg":"msg 3"},
{"uid":2,"created":1514813223,"msg":"msg 4"},
{"uid":1,"created":1514813283,"msg":"msg 5"},
{"uid":2,"created":1514813343,"msg":"msg 6"}],
"20": [{"uid":3,"created":1514813403,"msg":"msg 7"},
{"uid":4,"created":1514813463,"msg":"msg 8"},
{"uid":4,"created":1514813523,"msg":"msg 9"}]}
请通过使用PostgreSQL JSON 函数来实现吗?