我试图在手机中添加新联系人,但他只做前 12 个项目。我想尝试所有当前的 36 项,也许更多添加到电话联系人中。
while ((line = bufferedReader.readLine()) != null) {
System.out.println("[[DEBUG]] [DW-UPDATE] LINE: " + line);
String[] split = line.split(";", -1);
split[2] = split[2].replace("/", "").replace("-", "");
if (!contactExists(mActivity, split[2])) {
ops.add(ContentProviderOperation.newInsert(ContactsContract.RawContacts.CONTENT_URI)
.withValue(ContactsContract.RawContacts.ACCOUNT_TYPE, null)
.withValue(ContactsContract.RawContacts.ACCOUNT_NAME, null)
.withValue(ContactsContract.RawContacts.AGGREGATION_MODE, ContactsContract.RawContacts.AGGREGATION_MODE_DISABLED)
.build());
ops.add(ContentProviderOperation.newInsert(ContactsContract.Data.CONTENT_URI)
.withValueBackReference(ContactsContract.Data.RAW_CONTACT_ID, Integer.valueOf(split[0]))
.withValue(ContactsContract.Data.MIMETYPE, ContactsContract.CommonDataKinds.StructuredName.CONTENT_ITEM_TYPE)
.withValue(ContactsContract.CommonDataKinds.StructuredName.DISPLAY_NAME, split[1])
.build());
ops.add(ContentProviderOperation.newInsert(ContactsContract.Data.CONTENT_URI)
.withValueBackReference(ContactsContract.Data.RAW_CONTACT_ID, Integer.valueOf(split[0]))
.withValue(ContactsContract.Data.MIMETYPE, ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE)
.withValue(ContactsContract.CommonDataKinds.Phone.NUMBER, split[2])
.withValue(ContactsContract.CommonDataKinds.Phone.TYPE,ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE)
.build());
try {
mActivity.getContentResolver().applyBatch(ContactsContract.AUTHORITY, ops);
} catch (Exception e) {
e.printStackTrace();
}
}
}
函数联系存在:
public boolean contactExists(Activity _activity, String number) {
Uri lookupUri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(number));
String[] mPhoneNumberProjection = { ContactsContract.PhoneLookup._ID, ContactsContract.PhoneLookup.NUMBER, ContactsContract.PhoneLookup.DISPLAY_NAME };
Cursor cur = _activity.getContentResolver().query(lookupUri, mPhoneNumberProjection, null, null, null);
try {
if (cur.moveToFirst()) {
return true;
}
} finally {
if (cur != null)
cur.close();
}
return false;
}// contactExists
我必须做什么,才能更好地工作?