8

我做了这样的设计

在此处输入图像描述

如何用css遮盖背景？

我试过这样的代码

.img-poster {
  display: block;
  max-width: 100%;
  -webkit-mask-image: url(https://cdn.pbrd.co/images/GYiCod1.png), url(https://cdn.pbrd.co/images/GYiCQsM.png);
  -webkit-mask-position: bottom center, center center;
  -webkit-mask-repeat: no-repeat, no-repeat;
}

.add {
  -webkit-mask-composite: add;
}
<section class="section poster-container">
  <img src="https://imagejournal.org/wp-content/uploads/bb-plugin/cache/23466317216_b99485ba14_o-panorama.jpg" alt="" class="img-poster add img-responsive">
</section>

我使用的蒙版图像是

https://i.stack.imgur.com/fg2k5.png

https://i.stack.imgur.com/zmylJ.png

你们能告诉我我的代码有什么问题吗？我知道我可以只导入到 png，但我尝试使用 css

4

2 回答 2

8

您只需要考虑一个图像，它是蒙版的底部，然后对另一部分使用简单的渐变。你也不需要mask-composite. 只需调整大小/位置，使两个蒙版不重叠：

.img-poster {
  display: block;
  max-width: 100%;
  -webkit-mask:  
     linear-gradient(#fff,#fff)              top,
     url(https://i.ibb.co/5WvbqgG/zmylJ.png) bottom;
  -webkit-mask-size:
     100% calc(100% - 30px),
     auto 30px;
  -webkit-mask-repeat: repeat-x;
  mask:  
     linear-gradient(#fff,#fff)              top,
     url(https://i.ibb.co/5WvbqgG/zmylJ.png) bottom;
  mask-size:
     100% calc(100% - 30px),
     auto 30px;
  mask-repeat: repeat-x;
}
<section class="section poster-container">
  <img src="https://imagejournal.org/wp-content/uploads/bb-plugin/cache/23466317216_b99485ba14_o-panorama.jpg" alt="" class="img-poster add img-responsive">
</section>

于 2017-12-15T09:30:16.967 回答
2

SVG+滤镜解决方案

在图像中创建锯齿状边缘的SVG解决方案不需要使用带有锯齿状边缘的图案的光栅图像。因此，这种 SVG 解决方案可以应用于任何图像并使其具有自适应性。

考虑使用相同的图像创建锯齿状边缘 2 次。过滤器应用于较低的图像，因此，它变得更大一些。原始图像叠加在顶部，因此边缘上的牙齿变得可见。为了只在下边缘留下牙齿，我们在侧边缘用面罩切除了不必要的牙齿。 

.container {
 width:90vw;
 height:90vh;
 }
<div class="container">
<svg version="1.1" xmlns="http://www.w3.org/2000/svg" 
    xmlns:xlink="http://www.w3.org/1999/xlink"
	  viewBox="0 0 1800 900" >
 <defs> 
   <mask id="msk1"> 
        <rect x="100%" y="100%"  fill="white" /> 
      <rect x="1700" y="0" width="50" height="900" fill="white" />
   </mask>
     <filter id="displacementFilter">
     <feTurbulence type="turbulence" baseFrequency="0.01 0.01"
        numOctaves="2" result="turbulence" seed="1"/>
    <feDisplacementMap in2="turbulence" in="SourceGraphic"
        scale="65" xChannelSelector="R" xChannelSelector="G" yChannelSelector="B"/>
    </filter>	   
 </defs> 
        
       <!-- The image is processed by a filter and therefore overall dimensions have increased due to the height of the teeth -->
   <image   filter="url(#displacementFilter)" xlink:href="https://i.stack.imgur.com/paWbQ.jpg.jpg" width="1700" height="850" />
	   <rect mask="url(#msk1)" x="1700" y="0" width="50" height="900" fill="white" /> 
	   <!-- The same original image, but without filters  -->
	 <image x="0"  xlink:href="https://i.stack.imgur.com/paWbQ.jpg.jpg" width="1700" height="850" />
</svg>	
</div>

另一个图像 

 .container {
 width:90vw;
 height:90vh;
 }
<div class="container">
<svg version="1.1" xmlns="http://www.w3.org/2000/svg" 
    xmlns:xlink="http://www.w3.org/1999/xlink"
	  viewBox="0 0 1800 900" >
 <defs> 
   <mask id="msk1"> 
        <rect x="100%" y="100%"  fill="white" /> 
      <rect x="1700" y="0" width="50" height="900" fill="white" />
   </mask>
     <filter id="displacementFilter">
     <feTurbulence type="turbulence" baseFrequency="0.01 0.01"
        numOctaves="2" result="turbulence" seed="1"/>
    <feDisplacementMap in2="turbulence" in="SourceGraphic"
        scale="75" xChannelSelector="R" xChannelSelector="G" yChannelSelector="B"/>
    </filter>	   
 </defs> 
        
       <!-- The image is processed by a filter and therefore overall dimensions have increased due to the height of the teeth -->
   <image   filter="url(#displacementFilter)" xlink:href="https://i.stack.imgur.com/kaYSe.jpg" width="1700" height="850" />
	   <rect mask="url(#msk1)" x="1700" y="0" width="50" height="900" fill="white" /> 
	   <!-- The same original image, but without filters  -->
	 <image x="0"  xlink:href="https://i.stack.imgur.com/kaYSe.jpg" width="1700" height="850" />
</svg>	
</div>

于 2020-03-03T19:19:32.310 回答