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我试图通过unionSpatialPolygonsoraggregate函数溶解内部多边形来生成六边形地图的轮廓。我得到了不溶解的杂散十六进制......一个显示问题的虚拟示例:

# grab a dummy example shape file
library(raster)
g <- getData(name = "GADM", country = "GBR", level = 2)
# par(mar = rep(0,4))
# plot(g)

# create a hexagonal cartogram
# library(devtools)
# install_github("sassalley/hexmapr")    
library(hexmapr)
h <- calculate_cell_size(shape = g, seed = 1,
                         shape_details = get_shape_details(g), 
                         learning_rate = 0.03, grid_type = 'hexagonal')
i <- assign_polygons(shape = g, new_polygons = h)
par(mar = rep(0,4))
plot(i)

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# dissolve the polygons to get coastline
library(maptools)
j <- unionSpatialPolygons(SpP = i, IDs = rep(1, length(i)))
par(mar = rep(0,4))
plot(j)

# same result with aggregate in the raster package
k <- aggregate(x = i)
par(mar = rep(0,4))
plot(k)

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使用我实际使用的 shapefile(不适用于英国),我得到了更多的杂散六边形 - 有些是完整的 - 有些不是。

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1 回答 1

2

Roger Bivand 建议的解决方案(通过电子邮件交换):

 g1 <- spTransform(x = g, CRSobj = CRS("+init=epsg:27700"))
 # cellsize from calculate_cell_size() above
 h1 <- spsample(x = g1, type="hexagonal", cellsize=38309) 
 i2 <- HexPoints2SpatialPolygons(hex = h1) 
 j2 <- unionSpatialPolygons(SpP = i2, IDs = rep(1, length(i2)))
 plot(j2)

即避免assign_polygons()在 hexmapr 中使用 1)spsample生成形状位置和 2)HexPoints2SpatialPolygons用于六边形网格(均在sp封装中)。

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于 2017-12-07T05:22:43.330 回答