我无法将此 SQL Server 代码转换为 Oracle 代码。我不是 SQL 专家,任何人都可以帮助将此代码转换为与 Oracle 兼容的代码。
Declare @lvl as int
Declare @rows as int
DECLARE @foo as Table(
KV_MANAGERNR int,
KV_PERSONNR varchar(10),
ord int,
lvl int)
INSERT @foo (KV_MANAGERNR, KV_PERSONNR, ord, lvl)
select KV_MANAGERNR, KV_PERSONNR, row_number() over(order by KV_PERSONNR), 0
from PERSONSMANAGER where KV_MANAGERNR='127723'
set @rows=@@ROWCOUNT
set @lvl=0
--Do recursion
WHILE @rows > 0
BEGIN
set @lvl = @lvl + 1
INSERT @foo (KV_MANAGERNR, KV_PERSONNR, ord, lvl)
SELECT DISTINCT b.KV_MANAGERNR, b.KV_PERSONNR, row_number() over(order
by b.KV_PERSONNR), @lvl
FROM PERSONSMANAGER b
inner join @foo f on b.KV_MANAGERNR = f.KV_PERSONNR
--might be multiple paths to this recursion so eliminate duplicates
left join @foo dup on dup.KV_PERSONNR = b.KV_PERSONNR
WHERE f.lvl = @lvl-1 and dup.KV_PERSONNR is null
set @rows=@@ROWCOUNT
END
SELECT DISTINCT KV_PERSONNR from @foo order by KV_PERSONNR