以下是 BigQuery 标准 SQL
#standardSQL
SELECT customer_id, item_purchased, purchase_date,
(CASE WHEN
ROW_NUMBER() OVER (PARTITION BY customer_id ORDER BY purchase_date ASC) =
COUNT(*) OVER (PARTITION BY customer_id)
AND SUM(DISTINCT (CASE FORMAT_DATE('%Y%m', purchase_date)
WHEN '201709' THEN 1 WHEN '201710' THEN 2 ELSE 0 END))
OVER(PARTITION BY customer_id) = 3
THEN 1 ELSE 0
END) AS custom_coded
FROM `project.dataset.table`
您可以使用问题中的虚拟数据测试/玩上面的内容
#standardSQL
WITH `project.dataset.table` AS (
SELECT 288 customer_id, 'Rice' item_purchased, DATE '2017-09-02' purchase_date UNION ALL
SELECT 288, 'Rice', DATE '2017-09-02' UNION ALL
SELECT 288, 'Rice', DATE '2017-09-06' UNION ALL
SELECT 879, 'Plate', DATE '2017-09-01' UNION ALL
SELECT 879, 'Plate', DATE '2017-09-25' UNION ALL
SELECT 879, 'Plate', DATE '2017-10-25' UNION ALL
SELECT 879, 'Plate', DATE '2017-10-27'
)
SELECT customer_id, item_purchased, purchase_date,
(CASE WHEN
ROW_NUMBER() OVER (PARTITION BY customer_id ORDER BY purchase_date ASC) =
COUNT(*) OVER (PARTITION BY customer_id)
AND SUM(DISTINCT (CASE FORMAT_DATE('%Y%m', purchase_date)
WHEN '201709' THEN 1 WHEN '201710' THEN 2 ELSE 0 END))
OVER(PARTITION BY customer_id) = 3
THEN 1 ELSE 0
END) AS custom_coded
FROM `project.dataset.table`
ORDER BY customer_id, purchase_date
结果是
customer_id item_purchased purchase_date custom_coded
288 Rice 2017-09-02 0
288 Rice 2017-09-02 0
288 Rice 2017-09-06 0
879 Plate 2017-09-01 0
879 Plate 2017-09-25 0
879 Plate 2017-10-25 0
879 Plate 2017-10-27 1