-1

所以，我试图在我的代码中设置输入值的精度。我希望在精度之后用两个小数点打印这些值，尽管我不确定如何。

这是我的代码。

#include <iostream>
#include <iomanip>

float uphill, wellD, waterLvl, buckVol;
float buckAscRate, downHill, volume;
float last;
float timeReq;

int scene = 1;





void timeRequired()
{
    std::setw(2);
    std::setprecision(2);

    std::cout << "Scenario " << scene << ":" << std::endl;
    std::cout << "up hill" << "          " << uphill << " sec" << std::endl;
    std::cout << "well diamter" << "          " << wellD << " in" << std::endl;
    std::cout << "water level" << "          " << waterLvl << " in" << std::endl;
    std::cout << "bucket volume" << "          " << buckVol << " cu ft" << std::endl;
    std::cout << "bucket ascent rate" << "          " << buckAscRate << " in/sec" << std::endl;
    std::cout << "down hill" << "          " << downHill << " sec" << std::endl;
    std::cout << "required volume" << "          " << volume << " cu ft" << std::endl;

    timeReq = (uphill + downHill);

    std::cout << "TIME REQUIRED" << "          " << timeReq << " sec" << std::endl;

    std::cout << " " << std::endl;



}

void scenarioCONT()
{
    do
    {
        std::cin >> wellD;
        std::cin >> waterLvl;
        std::cin >> buckVol;
        std::cin >> buckAscRate;
        std::cin >> downHill;
        std::cin >> volume;
        std::cin >> last;

        if (uphill <= 1) uphill = 2;
        if (wellD <= 0) wellD = 1;
        if (waterLvl <= 0) waterLvl = 1;
        if (buckVol <= 0) buckVol = 1;
        if (buckAscRate <= 0) buckAscRate = 1;
        if (downHill <= 0) buckAscRate = 1;
        if (volume <= 0) volume = 1;

        if (last > 1)
        {
            uphill = last;
            scenarioCONT();

        }



    } while (last != 0);



}
void scenario()
{
    do
    {
        std::cin >> uphill;
        std::cin >> wellD;
        std::cin >> waterLvl;
        std::cin >> buckVol;
        std::cin >> buckAscRate;
        std::cin >> downHill;
        std::cin >> volume;
        std::cin >> last;

        if (uphill <= 1) uphill = 2;
        if (wellD <= 0) wellD = 1;
        if (waterLvl <= 0) waterLvl = 1;
        if (buckVol <= 0) buckVol = 1;
        if (buckAscRate <= 0) buckAscRate = 1;
        if (downHill <= 0) buckAscRate = 1;
        if (volume <= 0) volume = 1;

        if (last > 1)
        {
            timeRequired();
            uphill = last;
            scenarioCONT();

        }
            scene++;
            timeRequired();


    } while (last != 0);


}





int main()
{

    scenario();

    system("pause");
}

我被告知使用 ionmanip 来设置精度，尽管我不是 100% 知道如何做到这一点。有什么建议么？

4

2 回答 2

0

你可以使用std::setprecision函数。下面的例子直接取自http://www.cplusplus.com/reference/iomanip/setprecision/

  double f =3.14159;
  std::cout << std::setprecision(5) << f << '\n';
  std::cout << std::setprecision(9) << f << '\n';
于 2017-12-04T04:44:39.077 回答
0

如果要输出 2 个十进制数字，则应使用std::fixed, 和std::setprecision().

看看这里。

为了更容易理解，这里是一个例子： cout << setprecision(2)<< 3.1415;输出3.1（总共2位）和

cout << setprecision(2)<<fixed<< 3.1415;输出3.14（浮点数后 2 位）

于 2017-12-04T09:43:32.217 回答