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我有一个文件夹“Images-2”，其中有 100 多个子文件夹，这些子文件夹每个文件夹包含一个图像。def main()打开每个图像，并def run(img)获取图像并处理它，但现在我无法将该图像保存在它的子文件夹中。

例如def mainc:/Images-2/1/1.png （1 是文件夹名称，所以我在 Images-2 中有 100 个文件夹）

如果条件将处理后的图像（zero.png）保存在文件夹 Images-2/1/ 中

它如何用于 100 个文件夹，每个文件夹 1 张图像？

def run(img):
  data = img.load()
  width, height = img.size
  output_img = Image.new("RGB", (100, 100))
  Zero=np.zeros(shape=(100, 100),dtype=np.uint8)

  for (x, y) in labels:
            component = uf.find(labels[(x, y)])
            labels[(x, y)] = component
            path='C:/Python27/cclabel/Images-2/'
            if labels[(x, y)]==0:
                Zero[y][x]=int(255)
                Zeroth = Image.fromarray(Zero)
                for root, dirs in os.walk(path):
                    print root
                    print dirs
                    Zeroth.save(path+'Zero'+'.png','png')
def main():
    # Open the image
    path="C:/Python27/cclabel/Images-2/"
    for root, dirs, files in os.walk(path):
        for file_ in files:
            img = Image.open(os.path.join(root, file_))
            img = img.point(lambda p: p > 190 and 255)
            img = img.convert('1')
            (labels, output_img) = run(img)

if __name__ == "__main__": main()
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1 回答 1

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你打os.walk了两次电话。那是你的问题。这就是我在评论中的意思：

def run(dirname, img):
    data = img.load()
    width, height = img.size
    output_img = Image.new("RGB", (100, 100))
    Zero=np.zeros(shape=(100, 100), dtype=np.uint8)

    for (x, y) in labels:
        component = uf.find(labels[(x, y)])
        labels[(x, y)] = component
        path = 'C:/Python27/cclabel/Images-2/'
        if labels[(x, y)] == 0:
            Zero[y][x] = 255
            Zeroth = Image.fromarray(Zero)
            Zeroth.save(os.path.join(dirname, 'Zero.png'), 'png')


def main():
    path = "C:/Python27/cclabel/Images-2/"
    for root, dirs, files in os.walk(path):
        for file_ in files:
            img = Image.open(os.path.join(root, file_))
            img = img.point(lambda p: p > 190 and 255)
            img = img.convert('1')
            (labels, output_img) = run(root, img)


if __name__ == "__main__":
    main()
于 2017-12-03T12:30:38.577 回答