2

使用以下代码将字节 [] 转换为字符串时,我发现奇怪的占用堆

package main

import (
  "bytes"
  "fmt"
  "net/http"
  _ "net/http/pprof"
  "strings"
  "time"
)

var (
  c = make(chan int, 500000)
)

func main() {
  go func() {
    http.ListenAndServe(":8080", nil)
  }()
  f := func(ss []string) {
    fmt.Println(ss)
    time.Sleep(time.Millisecond)
    <-c
  }
  for {
    c <- 1
    bs := bytes.NewBufferString("A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z").Bytes()
    fmt.Println(bs) // will raise memory leak after marked as comment???
    s := string(bs)
    ss := strings.Split(s, ",")
    go f(ss)
  }
}
  1. 没有fmt.Println(bs)会逐渐耗尽记忆。

  2. 工作fmt.Println(bs)正常。我不明白发生了什么?我和我一起工作version go1.9.2 darwin/amd64

4

1 回答 1

4

没有内存泄漏:
您正在使用500000并发 goroutines,您只需要限制(减少)并发 goroutines 的数量,例如:

c := make(chan int, runtime.NumCPU())

试试这个(看看这个编辑的结尾):

package main

import (
    "bytes"
    "fmt"
    "runtime"
    "strings"
    "time"
)

func main() {
    c := make(chan int, runtime.NumCPU())
    for {
        c <- 1
        bs := bytes.NewBufferString("A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z").Bytes()
        s := string(bs)
        ss := strings.Split(s, ",")
        go func(ss []string) {
            fmt.Println(ss)
            time.Sleep(time.Millisecond)
            <-c
        }(ss)
    }
}

您的代码:

package main

import (
    "bytes"
    "fmt"
    "net/http"
    _ "net/http/pprof"
    "strings"
    "time"
)

var (
    c = make(chan int, 500000)
)

func main() {
    go func() {
        http.ListenAndServe(":8080", nil)
    }()
    f := func(ss []string) {
        fmt.Println(ss)
        time.Sleep(time.Millisecond)
        <-c
    }
    for {
        c <- 1
        bs := bytes.NewBufferString("A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z").Bytes()
        // fmt.Println(bs) // will raise memory leak after marked as comment???
        s := string(bs)
        ss := strings.Split(s, ",")
        go f(ss)
    }
}

它在一段时间后达到稳定状态,甚至减少了内存使用:

// Mem          CPU time:
// 5,464,208K 0:1:20
// 5,468,208K 0:2:20
// 5,469,608K 0:3:20
// 5,469,844K 0:4:20
// 5,469,844K 0:5:20
// 5,469,848K 0:6:20
// 5,469,848K 0:7:20 fixed
// 5,469,848K 0:8:20 fixed
// 5,469,616K 0:9:20 reduced
于 2017-12-03T07:25:26.080 回答