以下是 BigQuery 标准 SQL
#standardSQL
SELECT
column1,
MAX(IF(condition = 1, column2, '')) column2,
SUM(value)sumOfValue
FROM `project.dataset.table`
GROUP BY column1
您可以使用以下问题中的示例来测试/玩它
#standardSQL
WITH `project.dataset.table` AS (
SELECT 1 column1, 'ABC' column2, 1 condition, 1 value UNION ALL
SELECT 1, 'строка 2', 0, 1 UNION ALL
SELECT 1, 'строка 3', 0, 1 UNION ALL
SELECT 1, 'строка 4', 0, 1 UNION ALL
SELECT 1, 'строка 5', 0, 1 UNION ALL
SELECT 1, 'строка 6', 0, 1 UNION ALL
SELECT 2, 'BCD', 1, 1 UNION ALL
SELECT 2, 'строка 2', 0, 1 UNION ALL
SELECT 2, 'строка 3', 0, 1
)
SELECT
column1,
MAX(IF(condition = 1, column2, '')) column2,
SUM(value)sumOfValue
FROM `project.dataset.table`
GROUP BY column1
结果如预期(我认为)
column1 column2 sumOfValue
1 ABC 6
2 BCD 3
上述解决方案假设每组 column1 只有一行条件 = 1。如果不是这种情况 - 上面只会给你来自 column2 的一个(MAX)值。如果您需要对所有这些值进行分组 - 请参阅下面的选项
#standardSQL
WITH `project.dataset.table` AS (
SELECT 1 column1, 'ABC' column2, 1 condition, 1 value UNION ALL
SELECT 1, 'строка 2', 0, 1 UNION ALL
SELECT 1, 'строка 3', 1, 1 UNION ALL
SELECT 1, 'строка 4', 0, 1 UNION ALL
SELECT 1, 'строка 5', 1, 1 UNION ALL
SELECT 1, 'строка 6', 0, 1 UNION ALL
SELECT 2, 'BCD', 1, 1 UNION ALL
SELECT 2, 'строка 2', 0, 1 UNION ALL
SELECT 2, 'строка 3', 0, 1
)
SELECT
column1,
REGEXP_REPLACE(STRING_AGG(IF(condition = 1, CONCAT(column2, ','), ''),''), r',$', '') column2,
SUM(value)sumOfValue
FROM `project.dataset.table`
GROUP BY column1
在这种情况下,结果将是
column1 column2 sumOfValue
1 ABC,строка 3,строка 5 6
2 BCD 3